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PIT_PIT [208]
1 year ago
10

Two accounts each begin with a deposit of $9000. Both accounts have rates of 3.1%, but one account compounds interest once a yea

r while
the other account compounds interest continuously. Make a table that shows the amount in each account and the interest earned after one
year, five years, ten years, and 20 years.
Mathematics
1 answer:
Elodia [21]1 year ago
4 0
<h3 />

Given : Initial deposit or the principal amount = $ 9000

Rate of interest = 3.1 %

Compound interest annually

= principal (1 + r/ 100)^t

here put value principal rate and time period 1, 5 10 and 20 years

and we get the  amount for each time period        

than for interest = amount - principal we get interest    

as that we calculate all value:

given in the attachment

<h3>When do we use compound interest ?</h3>

When interest on a balance in a savings or investment account is reinvested, you receive compound interest, which results in higher interest payments. Money makes money, a wise man once said. And money makes money by making more money. Compound interest speeds up the long-term growth of your savings and investments.

To know  more about compound interest visit:
brainly.com/question/22621039

#SPJ13

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Which of the following is a solution to 2cos2x − cos x − 1 = 0?
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Answer:

Option A is correct.

Solution for the given equation is, x = 0^{\circ}

Step-by-step explanation:

Given that : 2\cos^2x -\cos x -1 =0

Let \cos x =y

then our equation become;

2y^2-y-1= 0           .....[1]

A quadratic equation is of the form:

ax^2+bx+c =0.....[2] where a, b and c are coefficient and the solution is given by;

x = \frac{-b\pm \sqrt{b^2-4ac}}{2a}

Comparing equation [1] and [2] we get;

a = 2 b = -1 and c =-1

then;

y = \frac{-(-1)\pm \sqrt{(-1)^2-4(2)(-1)}}{2(2)}

Simplify:

y = \frac{ 1 \pm \sqrt{1+8}}{4}

or

y = \frac{ 1 \pm \sqrt{9}}{4}

y = \frac{ 1 \pm 3}{4}

or

y = \frac{1+3}{4} and y = \frac{1 -3}{4}

Simplify:

y = 1 and y = -\frac{1}{2}

Substitute y = cos x we have;

\cos x = 1

⇒x = 0^{\circ}

and

\cos x = -\frac{1}{2}

⇒ x = 120^{\circ} \text{and} x = 240^{\circ}

The solution set:  \{0^{\circ}, 120^{\circ} , 240^{\circ}\}

Therefore, the solution for the given equation  2\cos^2x -\cos x -1 =0 is, 0^{\circ}





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vovangra [49]
1234 multiplied by 0.22(22%) equals 271.48.
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