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Andru [333]
2 years ago
11

Help please thank you

Mathematics
1 answer:
lara31 [8.8K]2 years ago
4 0

One of the rules of logarithms is as follows;

\begin{gathered} \log _ab=x \\ Is\text{ equivalent to,} \\ a^x=b \end{gathered}

We can now insert the corresponding values in the question provided, as shown below;

\begin{gathered} \log _2\frac{1}{16}=-4 \\ \text{This is equivalent to,} \\ 2^{-4}=\frac{1}{16} \end{gathered}

Note that, one of the rules of exponents, states that a number when raised to the power of a negative value, is equivalent to the reciprocal of that expression. An example is shown below;

a^{-x}=\frac{1}{a^x}

Therefore, our equation can now be re-written as follows;

\begin{gathered} 2^{-4}=\frac{1}{16} \\ \frac{1}{2^4}=\frac{1}{16}^{} \\ \frac{1}{16}=\frac{1}{16} \end{gathered}

However, the question requires the answer to be expressed in exponential form. Therefore,

\log _2\frac{1}{16}=2^{-4}

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Please help!!<br><br>Find BD​
Temka [501]

Answer:  8\sqrt{2}

==========================================================

Work Shown:

Focus entirely on triangle ABD (or on triangle BCD; both are identical)

The two legs of this triangle are AB = 8 and AD = 8. The hypotenuse is unknown, so we'll say BD = x.

Apply the pythagorean theorem.

a^2 + b^2 = c^2\\\\c = \sqrt{a^2 + b^2}\\\\x = \sqrt{8^2 + 8^2}\\\\x = \sqrt{2*8^2}\\\\x = \sqrt{8^2*2}\\\\x = \sqrt{8^2}*\sqrt{2}\\\\x = 8\sqrt{2}\\\\

So that's why the diagonal BD is exactly 8\sqrt{2}\\\\ units long

Side note: 8\sqrt{2} \approx 11.3137

6 0
3 years ago
-7 = -c - 29 Easy Points
Luden [163]

Hi there!  

»»————- ★ ————-««

I believe your answer is:  

c = - 22

»»————- ★ ————-««  

Here’s why:  

⸻⸻⸻⸻

\boxed{\text{Solving for 'c'...}}\\\\-7 = -c-29\\-------------\\\rightarrow -c -29 = -7\\\\\rightarrow -c - 29 + 29 = -7 + 29\\\\\rightarrow -c  = 22\\\\\rightarrow\frac{-c=22}{-1}\\\\\rightarrow \boxed{c = -22}

⸻⸻⸻⸻

»»————- ★ ————-««  

Hope this helps you. I apologize if it’s incorrect.  

5 0
3 years ago
Assume that 11 people, including the husband and wife pair, apply for 4 sales positions. People are hired at random.
Nastasia [14]
27% probability both husband and wife will be hired
5 0
3 years ago
∆abc is isosceles, ab = bc, and ch is an altitude. how long is ac, if ch = 84 cm and m∠hbc = m∠bac +m∠bch?
Tems11 [23]
Given that <span>∆abc is isosceles and ab = bc, then m<bac = m<acb and m<hbc = 180 - m<bac - m<acb

Given that </span><span>m∠hbc = m∠bac +m∠bch, then m<hbc + m<bch = m<bac + 2m<bch

But m<hbc + m<bch = 90°, thus 90° = m<bac + 2m<bch

</span><span>Also, m∠bac + m∠ach = 90° ⇒ m<bac + 2m<bch = m<bac + m<ach ⇒ 2m<bch = m<ach

Since, Δabc is isosceles with ab = bc ⇒ m<bac = m<acb.

Also, m<acb = m<ach + m<bch ⇒ m<acb = 3m<bch = m<bac

</span><span><span>Since m<bch : m<ach = 1 : 2 ⇒ bh : ah = 1 : 2

Thus, bh:bc:ch=1:3:\sqrt{8}

Given that ch = 84 cm, then

\frac{bc}{ch} = \frac{bc}{84} = \frac{3}{\sqrt{8}}  \\  \\ \Rightarrow bc= \frac{3\times84}{\sqrt{8}} =63\sqrt{2}=ab

Now, ah= \frac{2}{3} (63\sqrt{2})=42\sqrt{2}

ac= \sqrt{ch^2+ah^2}  \\  \\ = \sqrt{84^2+(42\sqrt{2})^2}  \\  \\ = \sqrt{7056+3528} = \sqrt{10584}  \\  \\ =42\sqrt{6}
</span> </span>
6 0
3 years ago
250 students were asked to choose their favorite color. How many more students chose purple than red as their favorite color? 26
nevsk [136]

Answer:

10 more students chose purple than red as their favorite color

Step-by-step explanation:

Step 1

Determine the proportion of students that chose each color

purple=26%

red=22%

Step 2

Use the expression for the number of students per color as follows;

Number of students per color=proportion per color×total number of students

for purple;

proportion that chose purple=26%

total number of students=250

replacing;

Number of students that chose purple=(26/100)×250=65 students

for red;

proportion that chose red=22%

total number of students=250

replacing;

Number of students that chose purple=(22/100)×250=55 students

Step 3

Difference=65-55=10

10 more students chose purple than red as their favorite color

6 0
3 years ago
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