1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
svetlana [45]
3 years ago
8

What is the midpoint of the segment shown below?

Mathematics
2 answers:
AlexFokin [52]3 years ago
6 0

Answer:

C

Step-by-step explanation:

The length of the segment is 7

2-7/2 = -3/2

(1,-3/2)

VashaNatasha [74]3 years ago
6 0

Hope this helps

Plz. mark as brainliest.

You might be interested in
Find the exact length of the third side.<br> 41<br> 9 <br> what’s the other side
vazorg [7]

Step-by-step explanation:

{d}^{2}  =  {a}^{2}  +  {b}^{2}  \\ 41 = 9 +  {b}^{2}  \\  {b}^{2}  = 41 - 9 \\  {b}^{2}  = 32 \\ b =  \sqrt{32}  \\ b = 5.66 \:

3 0
2 years ago
The sum of 8n²- 3n + 10 and 3n² - 6n-7 is ?​
vampirchik [111]

Step-by-step explanation:

= (8n² - 3n + 10) + (-3n² - 6n - 7)

= (8 - 3)n² + (-3 - 6)n + (10 - 7)

= 5n² - 9n + 3

Option → #1

5 0
2 years ago
16-5(3-1)= simplify
telo118 [61]

Combine like terms:

16 - 5(3-1)

16 - 5(2)

16-10

6

6 0
3 years ago
Read 2 more answers
Consider the following work breakdown structure: Time Estimates (days) Activity Precedes Optimistic Most Likely Pessimistic Star
Doss [256]

Answer: the probability that the critical path for this project will be completed within 210 days is 0.99725

Step-by-step explanation:

Given that;

Work break down is;  

 Time Estimates (days)

Activity  Precedes  Optimistic  Most Likely  Pessimistic  

Start          A,B              -                    -                   -  

A               C,D             44                50                 56  

B               D                45                60                  75  

C               E                42                45                   48  

D               F                31                 40                   49  

E               F                27                36                   39  

F              End            58                70                   82

we know that;

Expected Time = ( Optimistic Time + ( 4 × most likely time) + pessimistic time) / 6

and

Variance = [( pessimistic time - Optimistic time) / 6 ]²

so

ACTIVITY              EXPECTED TIME                                 VARIANCE

A                   (44 + (4 × 50) + 56) / 6 = 50                    ((56 - 44) / 6)² = 4

B                   (45 + (4 × 60) + 75) / 6 = 60                    ((75 - 45) / 6)² = 25

C                  (42 + (4 × 45) + 48) / 6 = 45                    ((48 - 42) / 6)² = 1

D                   (31 + (4 * 40) + 49) / 6 = 40                     ((49 - 31) / 6)² = 9

E                   (27 + (4 * 36) + 39) / 6 = 35                     ((39 - 27) / 6)² = 4

F                   (58 + (4 * 70) + 82) / 6 = 70                     ((82 - 58) / 6)² = 16

ACTIVITY     DURATION      ES        EF        LS        LF        SLACK

A                   50                      0        50         0         50            0

B                   60                      0        60        30        90           30

C                   45                     50       95        50        95            0

D                   40                     60      100        90       130          30

E                    35                    95       130        95       130           0

F                    70                    130     200       130      200           0

FORWARD PASS:

ES = MAXIMUM EF OF ALL PREDECESSOR ACTIVITIES; 0 IF NO PREDECESSORS ARE PRESENT.

EF = ES + DURATION OF THE ACTIVITY.

CRITICAL PATH = PATH WITH THE LONGEST COMBINED DURATION VALUE AND 0 SLACK.

CRITICAL PATH = ACEF

DURATION OF PROJECT = 200

Now the probability

VARIANCE OF CRITICAL PATH = SIGMA(VARIANCE OF THE CRITICAL PATH) = 25

STANDARD DEVIATION OF CRITICAL PATH = SQRT(VARIANCE OF CRITICAL PATH) = 5

EXPECTED TIME = DURATION OF THE PROJECT = CRITICAL PATH = 200

DUE TIME = 210

Z = (DUE TIME - EXPECTED TIME) / STANDARD DEVIATION OF CRITICAL PATH)

Z = (210 - 200) / 5 = 2

Now form the Normal Distribution Table;

Z = 0.99725

Therefore, the probability that the critical path for this project will be completed within 210 days is 0.99725

3 0
3 years ago
Find the value of x so that the function has the given value.<br><br> j (x) = -4/5x + 7; j (x) = -5
Murrr4er [49]

Answer:

x = 15

Step-by-step explanation:

Step 1: Define

j(x) = -4/5x + 7

j(x) = -5

Step 2: Substitute and Evaluate

-5 = -4/5x + 7

-12 = -4/5x

x = 15

5 0
3 years ago
Read 2 more answers
Other questions:
  • What's 20 percent of 40
    14·1 answer
  • CAN ANYONE HELP ME OUT ON THIS QUESTION WITH THE RIGHT Answer
    9·1 answer
  • Gabriela works at a nearby electronics store. she makes a commission of 14% on everything she sells. if she sells a camera for $
    5·1 answer
  • 9. An express delivery service advertises next-day delivery of any parcel it receives before 3PM. The actual success rate is 90%
    8·1 answer
  • 1) Anna solved the given equation. Is the solution correct? If not, determine the correct solution. x − 125 = 234 x = 125 + 234
    13·2 answers
  • The following frequency table summarizes a set of data.
    8·1 answer
  • ILL MARK YOU THE BRAINLYEST <br> PLEASE HELPPP look at attachment
    12·1 answer
  • WILL GIVE BRAINLIEST write an equation for the nth term of the sentence and find the 91st term -2,3,8,13,...
    6·1 answer
  • The vertices of a triangle are A(0,0),B(3,8) and C(9,0). What is the area of this triangle?
    14·1 answer
  • If an investor has a $5,000 pretax return, the state tax rate is 4.5%, and the federal tax rate is 22.0%, what is the real inves
    12·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!