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scZoUnD [109]
3 years ago
5

Misha wants to know how much wrapping paper is needed to cover a box with the dimensions shown.

Mathematics
1 answer:
Oliga [24]3 years ago
6 0

Answer:

D. 136 square inches :)

Step-by-step explanation:

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Which of the following are best described as lines that meet to form a right<br> angle?
Lynna [10]

Answer:

Two lines that intersect and form right angles are called perpendicular lines.

6 0
2 years ago
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Mrs. Carter's famous peanut butter cookies call for 1 cup of peanut butter for every 1 2 of a cup of oil. Today, she wants to ma
Alla [95]

Answer:

2 cups of peanut butter

Step-by-step explanation:

Mrs. Carter's famous peanut butter cookies call for 1 cup of peanut butter for every 1/2 of a cup of oil. Today, she wants to make a huge batch with 1 cup of oil. How much peanut butter should she use?

From the above question:

1/2 cup of oil = 1 cup of peanut butter

1 cup of oil = x

Cross Multiply

1/2x = 1 × 1

x = 1 ÷ 1/2

x = 1 × 2/1

x = 2 cups of peanut butter.

Therefore, for huge batch with 1 cup of oil, she should use 2 cups of peanut butter.

4 0
2 years ago
A line that includes the points 
timofeeve [1]

Answer:

p = -12

Step-by-step explanation:

I used graph paper to graph point (-7,-6) then i used the slope to continue to graph the rest of the points until i got to (-1,-12).

7 0
3 years ago
What is the slope of the line through ( 1 , − 1 ) and( 5 , − 7 )
Semenov [28]
M= y2-y1     -7- -1
      -------                 =   _-6_   = -3/2 
     x2-x1      5 -1            4 
3 0
3 years ago
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Divide line segments
ser-zykov [4K]

tis noteworthy that the segment contains endpoints of A and C and the point B is in between A and C cutting the segment in a 1:2 ratio,

\bf \textit{internal division of a line segment using ratios} \\\\\\ A(-9,-7)\qquad C(x,y)\qquad \qquad \stackrel{\textit{ratio from A to C}}{1:2} \\\\\\ \cfrac{A\underline{B}}{\underline{B} C} = \cfrac{1}{2}\implies \cfrac{A}{C}=\cfrac{1}{2}\implies 2A=1C\implies 2(-9,-7)=1(x,y)\\\\[-0.35em] ~\dotfill\\\\ B=\left(\frac{\textit{sum of "x" values}}{\textit{sum of ratios}}\quad ,\quad \frac{\textit{sum of "y" values}}{\textit{sum of ratios}}\right)\\\\[-0.35em] ~\dotfill

\bf B=\left(\cfrac{(2\cdot -9)+(1\cdot x)}{1+2}\quad ,\quad \cfrac{(2\cdot -7)+(1\cdot y)}{1+2}\right)~~=~~(-4,-6) \\\\[-0.35em] ~\dotfill\\\\ \cfrac{(2\cdot -9)+(1\cdot x)}{1+2}=-4\implies \cfrac{-18+x}{3}=-4 \\\\\\ -18+x=-12\implies \boxed{x=6} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{(2\cdot -7)+(1\cdot y)}{1+2}=-6\implies \cfrac{-14+y}{3}=-6 \\\\\\ -14+y=-18\implies \boxed{y=-4}

6 0
3 years ago
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