Answer:
y = (x + 7) (x + 6) (x − 3)
Step-by-step explanation:
Using rational root theorem, possible rational roots are:
±1, ±2, ±3, ±6, ±7, ±9, ±14, ±18, ±21, ±42, ±63, ±126
Using trial and error, we find that +3 is one of the roots.
There are 3 ways to continue from here: continue using trial and error to look for other rational roots; use long division to factor; or use grouping.
Using grouping:
y = x³ + 10x² + 3x − 126
y = x³ + 10x² − 39x + 42x − 126
y = x (x² + 10x − 39) + 42 (x − 3)
y = x (x + 13) (x − 3) + 42 (x − 3)
y = (x (x + 13) + 42) (x − 3)
y = (x² + 13x + 42) (x − 3)
y = (x + 7) (x + 6) (x − 3)
The formula to use is
A=p(1+(r/n))^(nt)
P= principle
R= rate
N= number of times it's compounded per year
T= time in years
Quadruple means 4 times
24000=6000(1+.035)^t
Divide by 6000
4= (1.035)^t
To bring the variable out of the power you take the log of both sides.
Log4= t Log1.035
Divide both sides by log1.035
(Log4)/(log1.035)=t
40.30=t
Answer:
The weight of the water in the pool is approximately 60,000 lb·f
Step-by-step explanation:
The details of the swimming pool are;
The dimensions of the rectangular cross-section of the swimming pool = 10 feet × 20 feet
The depth of the pool = 5 feet
The density of the water in the pool = 60 pounds per cubic foot
From the question, we have;
The weight of the water in Pound force = W = The volume of water in the pool given in ft.³ × The density of water in the pool given in lb/ft.³ × Acceleration due to gravity, g
The volume of water in the pool = Cross-sectional area × Depth
∴ The volume of water in the pool = 10 ft. × 20 ft. × 5 ft. = 1,000 ft.³
Acceleration due to gravity, g ≈ 32.09 ft./s²
∴ W = 1,000 ft.³ × 60 lb/ft.³ × 32.09 ft./s² = 266,196.089 N
266,196.089 N ≈ 60,000 lb·f
The weight of the water in the pool ≈ 60,000 lb·f
Answer:
5
Step-by-step explanation:
You just multiply the indices by the power so 1/6 x 6 = 1 and 5 to the power of 1 is just 5.
Answer:
7 1/2 feet of string to make 5 bracelets
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