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IRISSAK [1]
3 years ago
14

State if the triangles are similar. If so, how do you know they are similar and complete the similarity statement.

Mathematics
1 answer:
Mazyrski [523]3 years ago
7 0

Answer:

D. similar; AA similarity; ∆CSD

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Janet can plant nine feet of carrots in 15 minutes while her daughter Amy can plant 17 feet of carrots in half an hour.
Lena [83]

Answer:

Step-by-step explanation:

In order to find who is more efficient at planting carrots, we want to put both ratios in terms of the same amount of time.

For simplicity, lets see how many carrots each can make in 1 hour.

Janet:\\9ft \: in \: 15 \:minutes

\frac{9ft}{15min} = \frac{xft}{60min}\\x = \frac{60*9}{15} = 36

Janet can plant 36 feet of carrots in one hour

Amy:\\\frac{17ft}{30min} = \frac{xft}{60min}\\x = \frac{17*60}{30} = 34

Amy can plant 34 feet of carrots in one hour

So, Janet can plant carrots more quickly

6 0
3 years ago
Write and solve an equation to find the value of X
Mumz [18]
Angles on a straight line add up to 180 degrees so

45 + 3x = 180
Subtract 45 from both sides to remove the 45 on the left

3x = 135
Then divide both sides by 3
x = 45

Answer is X = 45
8 0
3 years ago
Read 2 more answers
What is the compund interest on 5,000 over 3 years at 5% interest
Katena32 [7]

Answer:

788.13  to the nearest hundredth.

Step-by-step explanation:

Let A be the total amount in the account after 3 years.

The formula is A = P(1 + x/100)^t .

Here P = 5000, x = 5 %  and the time t = 3. years.  

Amount after 3 years = 5000(1 + 5/100)^3

=  5788.13

So the Interest is 5788.13 - 5000

= 788.13.

8 0
3 years ago
Read 2 more answers
Johnny rode his bike 4/7 of a mile from his house to the lake on a straight path. then, he turned around and rode his bike 3/1/8
iren [92.7K]
I hope this helps you



3 1/8=3.8+1/8=25/8


25/8-4/7


25.7/8.7-4.8/7.8


175-32/56


143/56

2 31/56

7 0
3 years ago
Read 2 more answers
If
likoan [24]

It's easy to show that 7\tan(4x) is strictly increasing on x\in\left[0,\frac\pi8\right]. This means

M = \max \left\{7\tan(4x) \mid \dfrac\pi{16} \le x \le \dfrac\pi{12}\right\} = 7\tan(4x) \bigg|_{x=\pi/12} = 7\sqrt3

and

m = \min \left\{7\tan(4x) \mid \dfrac\pi{16} \le x \le \dfrac\pi{12}\right\} = 7\tan(4x) \bigg|_{x=\pi/16} = 7

Then the integral is bounded by

\displaystyle 7\left(\frac\pi{12} - \frac\pi{16}\right) \le \int_{\pi/16}^{\pi/12} 7\tan(4x) \, dx \le 7\sqrt3 \left(\frac\pi{12} - \frac\pi{16}\right)

\implies \displaystyle \boxed{\frac{7\pi}{48}} \le \int_{\pi/16}^{\pi/12} 7\tan(4x) \, dx \le \boxed{\frac{7\sqrt3\,\pi}{48}}

7 0
2 years ago
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