The region inside one leaf of r the area of the region is pi.20.
r =cos5θ
cos5θ =0
5θ=pi/2 ,5θ=3pi/2
θ=pi/10,θ=3pi/10
area of one leaf = ∫[pi/10 to 3pi/10](1/2)r2dθ
= ∫[pi/10 to 3pi/10](1/2)(cos5θ)2dθ
= ∫[pi/10 to 3pi/10](1/4)(1+cos10θ)dθ
=[pi/10 to 3pi/10](1/4)(θ+ (1/10)sin10θ)
=(1/4)((3pi/10)+ (1/10)sin3pi) -(1/4)((pi/10)+ (1/10)sinpi)
=(1/4)(3pi/10) -(1/4)(pi/10)
=(1/4)(2pi/10)
=pi/20
area of one leaf =pi.20.
Region area (calculus) Region area. The non-negative function given by y = f(x) represents a smooth curve on the closed interval [a, b].The area through the curve of f(x), the x-axis, and the perpendicular lines x = a and x = b The bounding region shown in Figure 1 is given by.
Learn more about the area of the region here: brainly.com/question/19053586
#SPJ4
