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snow_lady [41]
3 years ago
7

Evaluate. ( please please help me if I don’t pass this class I have to retake the year)

Mathematics
1 answer:
AlexFokin [52]3 years ago
5 0

Answer:

1/2

Step-by-step explanation:

I think. So sorry if wrong

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46 x 53 please show with work or something
lutik1710 [3]

Answer:

2,438

Step-by-step explanation:

    53

    46

______

     318

   212

_______

   2438

6 times 3 is 18. Put the 8 in the ones place and carry the 1 ~ 6 times 5 is 30. Add the carried 1 and you have 31. Put that next to the 8. ~ 4 times 3 is 12. put the 2 under the 1 in 318 and carry the 1. ~ 4 times 5 is 20. Add the carried 1 and you have 21. ~ Put that next to the 2. Now add 318 to 2120 and you have the answer of 12438.

5 0
3 years ago
What is the domain of the function? <br><img src="https://tex.z-dn.net/?f=y%20%3D%20%20%5Csqrt%5B3%5D%7Bx%20-%201%7D%20" id="Tex
BabaBlast [244]

Answer: The first option.

Step-by-step explanation:

This domain has no domain restrictions. Therefore, it covers all real numbers. x∈R

3 0
3 years ago
Write down one pro and one con of employment.
lapo4ka [179]

Answer:

Pro: Monthly income to pay bills, buy food ,etc

Con: You many feel tied down, you could get abused at work (taken advantage of)

8 0
3 years ago
Kurt wants to informally prove the converse of the Pythagorean Theorem by producing some evidence that supports it.
Elis [28]

Answer:

A and C

Step-by-step explanation:

I had it on a test

4 0
3 years ago
Find the area of the largest rectangle (with sides parallel to the coordinate axes) that can be inscribed in the region enclosed
garik1379 [7]
F(x) = 18-x^2 is a parabola having vertex at (0, 18) and opening downwards. 
g(x) = 2x^2-9 is a parabola having vertex at (0, -9) and opening upwards. 
By symmetry, let the x-coordinates of the vertices of rectangle be x and -x => its width is 2x. 
Height of the rectangle is y1 + y2, where y1 is the y-coordinate of the vertex on the parabola f and y2 is that of g.
 => Area, A 
= 2x (y1 - y2) 
= 2x (18 - x^2 - 2x^2 + 9) 
= 2x (27 - 3x^2) 
= 54x - 6x^3 
For area to be maximum, dA/dx = 0 and d²A/dx² < 0 
=> 54 - 18x^2 = 0 
=> x = √3 (note: x = - √3 gives the x-coordinate of vertex in second and third quadrants) 

d²A/dx² = - 36x < 0 for x = √3 
=> maximum area 
= 54(√3) - 6(√3)^3 
= 54√3 - 18√3 
= 36√3. 
4 0
3 years ago
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