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Alex787 [66]
1 year ago
10

Help please!!! add explanation

Mathematics
1 answer:
sleet_krkn [62]1 year ago
7 0

Answer:

the answer is 5

Step-by-step explanation:

You plug in -1 for the g equation.

Then you get -4 and then you plug that in as x for the f equation

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the company found that an experienced surveyor can survey a roadbed in 5 hours. An apprentice needs 8 hours to survey the same s
dedylja [7]
40 hours is the answer
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3 years ago
The mean of six numbers is 14. If one of the six numbers is removed, the mean becomes 5. What is the value of the number removed
Oliga [24]

Answer:

Remember, the mean is calculated by adding the scores together and then dividing by the number of scores you added. In this case, the mean would be 2 + 4 (add the two middle numbers), which equals 6. Then, you take 6 and divide it by 2 (the total number of scores you added together), which equals 3.

Step-by-step explanation:

Hope I helped.It's just a reminder of helpful things for means!

3 0
3 years ago
Read 2 more answers
Plz help this is important
zhenek [66]
You divide the x coordinates of the a and b

7 0
3 years ago
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Postal regulations specify that a parcel sent by priority mail may have a combined length and girth of no more than 132 in. Find
joja [24]

Answer:

v = 11264 in^3

Step-by-step explanation:

4 x + l =132

l=132- 4 x

v= h x^ 2

 = x ^ 2 (132 - 4 x )

= 132 x ^ 2 - 4 x^3

 = 4 ( 33 x^2 - x ^3)

d v/d x = 4 (66 x - 3 x^2)

         = 12 x ( 22 - x)

d v/d x = 0

when x = 0  or 22

So

h = 132 - 4 *22 = 44

So if the package is  44*16*16

v = 11264 in^3

So  4 x+l >= 132 But it should be minimum if 4 x+l contain smaller value

6 0
4 years ago
Find the volume of the solid formed by revolving the region bounded by the graphs of y = x^3, x = 2, and y = 1 about the y-axis.
vladimir1956 [14]

If you're using the shell method, the setup would be

\displaystyle2\pi\int_1^2x(x^3-1)\,\mathrm dx

Reasoning: consider just one shell (see the image below). The height of the shell is determined by the vertical distance between the curve y=x^3 and the line y=1. The radius of each shell is determined by the value of x, which can only range from 1 to 2 within the region of interest, and the height is determined exactly by x^3-1 at this x. Multiply by 2\pi to get the surface area of this infinitesimally thin cylindrical shell, then integrate along the interval [1, 2] to get the volume.

We have

\displaystyle2\pi\int_1^2x(x^3-1)\,\mathrm dx=2\pi\int_1^2(x^4-x)\,\mathrm dx=2\pi\left(\dfrac{x^5}5-\dfrac{x^2}2\right)\bigg|_1^2=\dfrac{47\pi}5

4 0
4 years ago
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