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Leya [2.2K]
3 years ago
7

At pizza king, a pizza cost $9.00 plus $1.75 for each additional topping

Mathematics
1 answer:
IRINA_888 [86]3 years ago
8 0

Answer:

9+1.75x

Step-by-step explanation:

Hope Your Thanksgiving Went Well, Here's Some Help Cleaning Up

-TheKoolKid1O1

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150 feet2 50 feet I hope this helps!

Step-by-step explanation:

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Since you are multiplying ⁷√x three times, you write it like this first, ⁷√x³, then according to one of the Six Exponential Rules, ⁿ√aᵐ = aᵐ\ⁿ, ⁷√x³ gets rewritten as x³\⁷.

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4 0
3 years ago
Seven apple women possessed respectively 20,40,60,80,100,120,and 140 apples, went to market and sold all their apples at the sam
ra1l [238]

Answer: Each woman sold her apples at the rate of seven apples for I¢, and 3¢ each for the odd ones which were left over. this made it possible for each to receive the same amount, which is 20¢.

Step-by-step explanation:

given data:

20,

40,

60,

80,

100,

120,

140.

solution.

first woman 20 apples

= 2 + 3 * 6¢.

= 20¢.

second woman 40 apples

= 5 + 5 * 3¢.

= 20¢.

third woman 60 apples

= 8 + 4 * 3¢.

= 20¢.

fourth woman 80 apples

= 11 + 3 * 3¢.

= 20¢.

fifth woman 100 apples

= 14 + 2 * 3¢.

= 20¢.

sixth woman 120 apples

= 17 + 1 * 3¢.

= 20¢.

seventh woman 140 apples

= 20 * 1¢.

= 20¢.

3 0
3 years ago
Which of the following is the greatest unit rate? *
Brrunno [24]

Answer:

It is the last one. (16 for 2 tickets)

Step-by-step explanation:

To make it a unit fraction you have to divide the denominator by itself to get 1. 2 divided by 2 equals 1. To keep the fraction equivalent divide the numerator by 2 as well. That equals 8. This makes the unit rate

1/8 Which is the biggest

7 0
3 years ago
Read 2 more answers
Inverse laplace of [(1/s^2)-(48/s^5)]
Katen [24]
**Refresh page if you see [ tex ]**

I am not familiar with Laplace transforms, so my explanation probably won't help, but given that for two Laplace transform F(s) and G(s), then \mathcal{L}^{-1}\{aF(s)+bG(s)\} = a\mathcal{L}^{-1}\{F(s)\}+b\mathcal{L}^{-1}\{G(s)\}

Given that \dfrac{1}{s^2} = \dfrac{1!}{s^2} and -\dfrac{48}{s^5} = -2\cdot\dfrac{4!}{s^5}

So you have \mathcal{L}^{-1}\left\{\dfrac{1}{s^2} - 2\cdot\dfrac{4!}{s^5}\right\} = \mathcal{L}^{-1}\left\{\dfrac{1}{s^2}\right\} - 2\mathcal{L}^{-1}\left\{\dfrac{4!}{s^5}\right\}

From Table of Laplace Transform, you have \mathcal{L}\{t^n\} = \dfrac{n!}{s^{n+1}} and hence \mathcal{L}^{-1}\left\{\dfrac{n!}{s^{n+1}}\right\} = t^n

So you have \mathcal{L}^{-1}\left\{\dfrac{1}{s^2}\right\} - 2\mathcal{L}^{-1}\left\{\dfrac{4!}{s^5}\right\} = \boxed{t-2t^4}.

Hope this helps...
7 0
3 years ago
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