Answer:
0.229
Step-by-step explanation:
Given that the difference between the two sample means follows anormal distribution with a mean of11.00 and standard deviation equal to1.4387
A statistician is interested in the effectiveness of a weight-loss supplement. She randomly selects two independent samples. Individuals in the first sample of size n1 = 24 take the weight-loss supplement. Individuals in the second sample of size n2 = 21 take a placebo. Individuals in both samples follow identical exercise and diet programs. At the end of the study, the statistician measures the weight loss (in percent) of each participant.
We find that mean difference actual = 13-2 = 11
Probability that difference >12 =P(Z>
)
=P(Z>0.742)=.0.229
<h3>
Answer:</h3>
For each birdhouse built, the total cost increases by $3.50.
<h3>
Step-by-step explanation:</h3>
Let's try some of the answers and see if they work.
The "initial cost" will be the cost when 0 birdhouses are built.
... f(0) = 3.5·0 +24 = 24 . . . . . clearly, not $3.50
Then increasing the number of birdhouses by 1, the cost is ...
... f(1) = 3.5·1 +24 = 27.5 . . . . . the cost has gone up (not down) by $3.50
Clearly the total cost to build 1 birdhouse is not $3.50. (It is $27.50.)
___
Our exploration of the formula leads us to conclude ...
... For each birdhouse built, the total cost increases by $3.50.
Answer:
To be precise, I think it's a pattern question, where you have to add 4 to each number. I'm not very sure though.
Answer: Ethan will have to spend 2 hours reading if 14 pages are left to read
Step-by-step explanation:
Given the equation
P=-30h+74
where p =number of pages left to read and
h= the number of hours he has spent reading
Therefore , if Ethan has 14 pages left to read, then the number of hours Ethan will have to read will be
P=-30h+74
14= -30h + 74
30h= 74-14
30h= 60
h = 60/30
h =2 hours
Ethan will have to spend 2 hours reading if 14 pages are left to read
