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olasank [31]
3 years ago
6

Please help. Algebra.

Mathematics
1 answer:
Korvikt [17]3 years ago
6 0

Answer:

(6, -3)

Step-by-step explanation:

sorry, i don't know what you have to write in the blanks.

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I need help with math
pantera1 [17]

Answer:

answer is y=-2x

Step-by-step explanation:

-2x because every time  the dot decreases

6 0
2 years ago
Write an equation the describes the line passing through point (-2,8) with slope 4/5
andre [41]

Answer:

point-slope form: y-8=\frac{4}{5}(x+2)

Step-by-step explanation:

hope this helps :)

7 0
2 years ago
How do you simplify this –34–23a+16a
Dafna11 [192]

Answer:

-34 -7a

Step-by-step explanation:

–34–23a+16a

Combine like terms

-34 -7a

8 0
3 years ago
Read 2 more answers
How does this polynomial identity work on numerical relationships?<br> (y + x) (ax + b)
Serggg [28]

Let us take 'a' in the place of 'y' so the equation becomes

(y+x) (ax+b)

Step-by-step explanation:

<u>Step 1:</u>

(a + x) (ax + b)

<u>Step 2: Proof</u>

Checking polynomial identity.

(ax+b )(x+a) = FOIL

(ax+b)(x+a)

ax^2+a^2x is the First Term in the FOIL

ax^2 + a^2x + bx + ab

(ax+b)(x+a)+bx+ab is the Second Term in the FOIL

Add both expressions together from First and Second Term  

= ax^2 + a^2x + bx + ab

<u>Step 3: Proof </u>

(ax+b)(x+a) = ax^2 + a^2x + bx + ab

Identity is Found .

Trying with numbers now

(ax+b)(x+a) = ax^2 + a^2x + bx + ab

((2*5)+8)(5+2) =(2*5^2)+(2^2*5)+(8*5)+(2*8)

((10)+8)(7) =(2*25)+(4*5)+(40)+(16)

(18)(7) =(50)+(20)+(56)

126 =126

3 0
3 years ago
List the sides of each triangle from shortest to greatest
True [87]

A) First, we need to calculate x. We can do this by doing: 180-(70+50), which is nothing but 60.

Since the largest angle is 60, it means that the side opposite of it is the largest side. Which in this case, side AB.

So the largest side is AB.

Now, let's take a look at the smallest angle which is <B, because AC is the opposite of this angle, it must also be the smallest side.

We're left with angle <50, which is "medium" sized? Obviously, this can just be put in the middle (Side BC)

So, for response A, you should get AC, BC, AB.

Now for problem B, it's the same steps we did above. If you replicate what we did you should get PQ, PR,RQ.

Please let me know how I did.

Happy studying!

3 0
3 years ago
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