The mechanical advantage of the pulley is 1.
<h2>Mechanical advantage</h2>
The ratio of the force produced by a machine to the force applied to it.
<h3>The formula for mechanical advantage.</h3>
Here,
is output force and
input force.
<h3>Given</h3>
A pulley is given.
<h3>To find </h3>
The mechanical advantage of the pulley.
<h3>How to find a mechanical advantage?</h3>
We know by Newton's first law.
P = W
where P is applied force
and W is the weight of the object.
Then
![\rm M.A. = \dfrac{F_o}{F_i}\\\\M.A. = \dfrac{P}{W}\\\\M.A. = \dfrac{P}{P}\\\\M.A. = 1](https://tex.z-dn.net/?f=%5Crm%20M.A.%20%3D%20%5Cdfrac%7BF_o%7D%7BF_i%7D%5C%5C%5C%5CM.A.%20%3D%20%5Cdfrac%7BP%7D%7BW%7D%5C%5C%5C%5CM.A.%20%3D%20%5Cdfrac%7BP%7D%7BP%7D%5C%5C%5C%5CM.A.%20%3D%201)
The mechanical advantage of the pulley is 1.
More about the mechanical advantage link is given below.
brainly.com/question/2565461
The answer is D.
y = 3x - 4
(5, 11)
11 = 3(5) - 4
11 = 15 - 4
11 = 11
(2, 2)
y = 3x - 4
2 = 3(2) - 4
2 = 6 - 4
2 = 2
Answer:
![E(X) = \sum_{i=1}^n X_i P(X_i)](https://tex.z-dn.net/?f=%20E%28X%29%20%3D%20%5Csum_%7Bi%3D1%7D%5En%20X_i%20P%28X_i%29%20)
And replacing we got:
![E(X) = 1*0.05 +2* 0.3 +3* 0.4 +4*0.25 = 2.85](https://tex.z-dn.net/?f=%20E%28X%29%20%3D%201%2A0.05%20%2B2%2A%200.3%20%2B3%2A%200.4%20%2B4%2A0.25%20%3D%202.85)
So we are going to expect about 2,85 automobiles for this case.
Step-by-step explanation:
For this case we define the random variable X as "number of automobiles lined up at a Lakeside Olds dealer at opening time (7:30 a.m.)" and we know the distribution for X is given by:
X 1 2 3 4
P(X) 0.05 0.30 0.40 0.25
The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete
For this case we can calculate the epected value with this formula:
![E(X) = \sum_{i=1}^n X_i P(X_i)](https://tex.z-dn.net/?f=%20E%28X%29%20%3D%20%5Csum_%7Bi%3D1%7D%5En%20X_i%20P%28X_i%29%20)
And replacing we got:
![E(X) = 1*0.05 +2* 0.3 +3* 0.4 +4*0.25 = 2.85](https://tex.z-dn.net/?f=%20E%28X%29%20%3D%201%2A0.05%20%2B2%2A%200.3%20%2B3%2A%200.4%20%2B4%2A0.25%20%3D%202.85)
So we are going to expect about 2,85 automobiles for this case.
Answer:
82
Step-by-step explanation:
All honesty I did 2*42=82 :) <3