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Softa [21]
1 year ago
14

Use the diagram to answer the following questions.125°Lx2X+10NmZNPMdegreesmZLPMdegrees

Mathematics
1 answer:
lutik1710 [3]1 year ago
4 0

For the angle MPN we know that is oposite to the angle QPL so the will be equal so:

\angle MPN=125º

Now with the value of MPN we can made an equation for x so:

125=2x+10

and we solve for x

\begin{gathered} 125-10=2x \\ \frac{115}{2}=x \\ 57.5=x \end{gathered}

and the angle LPM will be the complementari angle of 125 so:

\begin{gathered} \angle LPM=180-125 \\ \angle LPM=55º \end{gathered}

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If we sample from a small finite population without​ replacement, the binomial distribution should not be used because the event
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5/4324 = 0.001156337

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To better understand the hyper-geometric distribution consider the following example:

There are 100 senators in the US Congress, and suppose 60 of them are republicans  so 100 - 60 = 40 are democrats).

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Now, imagine there are 56 senators (56 lottery numbers), 6 are republicans (6 winning numbers and 50 losers), we extract a sample of 6 senators (the bettor selects 6 numbers). What is the probability that 4 senators are republicans? (What is the probability that 4 numbers are winners?).

<em>As we see, the situation is exactly the same,</em> but changing the numbers. So the answer would be

\large \frac{\binom{6}{4}\binom{56-6}{6-4}}{\binom{56}{6}}=\frac{\binom{6}{4}\binom{50}{2}}{\binom{56}{6}}

Now compute each combination separately:

\large \binom{6}{4}=\frac{6!}{4!2!}=15\\\\\binom{50}{2}=\frac{50!}{2!48!}=1225\\\\\binom{50}{6}=\frac{50!}{6!44!}=15890700

and now replace the values:

\large \frac{\binom{6}{4}\binom{50}{2}}{\binom{56}{6}}=\frac{15*1225}{15890700}=\frac{18375}{15890700}=\frac{5}{4324}

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If the decimal expression is preferred then divide the fractions to get 0.001156337

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