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inysia [295]
3 years ago
12

If i had a horizontal line that passes through (-5,9) what would the equation be

Mathematics
1 answer:
katrin2010 [14]3 years ago
6 0

A horizontal line goes from left to right on a graph. If a line is horizontal that means that all the values of y will be the same no matter what the x is. In this case all the y - values of this graph will be 9. This makes the equation of the line:

y = 9

Hope this helped!

~Just a girl in love with Shawn Mendes

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then, put -20 over 55

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the negative stands for decrease, so it's around 36% decrease
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3 years ago
It takes 4 pounds of apples to make 6 cups of applesauce.
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Step-by-step explanation:

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2 years ago
Read 2 more answers
UW= 2 and UX=y. Write an expression for WX
Eddi Din [679]
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Next: UW=m and WX=y+14  write expression for UX

First, divide each term by W and simplify. U=m/W, WX=y+14. Next, solve the equation for Y. Move y from the right side of the equation to the left side. Still, U=m/W and y=-14+WX.  We must reorder -14 and WX. U=m/w and y=WX-14.
Replace the variable U with m/W in the expression to (m/W)X. Next, simplify (m/W)X. Now, write X and a fraction with denominator 1. Looks like this
fractions are side by side m/W X/1 . Multiply, m/W and X/1 to get mX/W.
mX/W is your final expression for UW=m and WX=y+14 expression for UX.
8 0
3 years ago
Find the exact value of csc theta if tan theta = sqrt3 and the terminal side of theta is in Quadrant III.
WARRIOR [948]

Answer:

3rd option

Step-by-step explanation:

Using the identities

cot x = \frac{1}{tanx}

csc² x = 1 + cot² x

Given

tanθ = \sqrt{3} , then cotθ = \frac{1}{\sqrt{3} }

csc²θ = 1 + (\frac{1}{\sqrt{3} } )² = 1 + \frac{1}{3} = \frac{4}{3}

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8 0
3 years ago
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