On a number line, point A is at 5, and point B is at -10. Point C is on AB such that the ratio of AC to CB is 1: 3. Find D on BC

Question

1 year ago

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such that the ratio of BD to DC is 3:5.

1 answer:

Ad libitum [116K] · Answer 1 · 2024-08-06T14:29:36+03:00

The location of point D on the number line is -5.15625

<h3>How to determine the location of point D?</h3>

The given parameters are:

A = 5

B = -10

AC : CB = 1 : 3

This means that

C = AC/(AC + AB) * (A - B)

This gives

C = 1/4 * (5 + 10)

Evaluate

C = 3.75

Also, we have:

BD : DC = 3 : 5

So, we have:

D = BD/(BD + DC) * (B - C)

This gives

D = 3/8 * (-10 - 3.75)

Evaluate

D = -5.15625

Hence, the location of point D on the number line is -5.15625