Question

Dave ordered dinner for a party of 10 people. Three people ordered the $4.75 chicken dinner, two people ordered the $4.95 fish dinner, and five had the beef dinner at a cost of $6.75 each. what was the average cost of each dinner at Dave's party?

Answer 1

Answer:

The average cost of each dinner at Dave's party is $5.79.

Step-by-step explanation:

Given:

Dave ordered dinner for a party of 10 people.

Three people ordered the $4.75 chicken dinner, two people ordered the $4.95 fish dinner, and five had the beef dinner at a cost of $6.75 each.

Now, to find the average cost of each dinner at Dave's party.

So, we get the total amount for the dinner:

Three people ordered the $4.75 chicken dinner.

$4.75\times 3=14.25$

Two people ordered the $4.95 fish dinner.

$4.95\times 2=9.90$

Five had the beef dinner at a cost of $6.75.

$6.75\times 5=33.75$

Total amount of dinner = $14.25+9.90+33.75=\ 57.90.$

Now, to get the average cost of each dinner of 10 people we divide the total amount of dinner by 10:

$57.90\div 10$

$=\ 5.79.$

Therefore, the average cost of each dinner at Dave's party is $5.79.