Answer:
The average cost of each dinner at Dave's party is <u>$5.79</u>.
Step-by-step explanation:
Given:
Dave ordered dinner for a party of 10 people.
Three people ordered the $4.75 chicken dinner, two people ordered the $4.95 fish dinner, and five had the beef dinner at a cost of $6.75 each.
Now, to find the average cost of each dinner at Dave's party.
So, we get the total amount for the dinner:
Three people ordered the $4.75 chicken dinner.

Two people ordered the $4.95 fish dinner.

Five had the beef dinner at a cost of $6.75.

Total amount of dinner = 
Now, to get the average cost of each dinner of 10 people we divide the total amount of dinner by 10:


Therefore, the average cost of each dinner at Dave's party is $5.79.