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1 year ago

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Which choices are equivalent to the expression below? check all that apply. square root of 6 * square root of 10A. 2 sqrt 15b. s

qrt 16c. sqrt 4x sqrt 15d. 60e. 20f. sqrt 60

1 answer:

Anon25 [30]1 year ago

6 0

$\begin{gathered} \sqrt[]{6}\times\sqrt[]{10} \\ \sqrt[]{60} \\ \sqrt[]{4\times15} \\ \sqrt[]{4}\times\sqrt[]{15} \\ 2\sqrt[]{15} \end{gathered}$

Hence, the correct options are Option A and Option C

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What is 5x÷6=20<br> Pls help I can't figure it out

grin007 [14]

Answer:

x= 24

Step-by-step explanation:

5x=20*6

x=120/5

x=24

Hope this helps! Plz mark as brainliest! :)

4 0

3 years ago

Read 2 more answers

Apply the method of undetermined coefficients to find a particular solution to the following system.wing system.

jarptica [38.1K]

$y''-y'+y=\sin x$

The corresponding homogeneous ODE has characteristic equation $r^2-r+1=0$ with roots at $r=\dfrac{1\pm\sqrt3}2$ , thus admitting the characteristic solution

$y_c=C_1e^x\cos\dfrac{\sqrt3}2x+C_2e^x\sin\dfrac{\sqrt3}2x$

For the particular solution, assume one of the form

$y_p=a\sin x+b\cos x$

${y_p}'=a\cos x-b\sin x$

${y_p}''=-a\sin x-b\cos x$

Substituting into the ODE gives

$(-a\sin x-b\cos x)-(a\cos x-b\sin x)+(a\sin x+b\cos x)=\sin x$

$-b\cos x+a\sin x=\sin x$

$\implies a=1,b=0$

Then the general solution to this ODE is

$\boxed{y(x)=C_1e^x\cos\dfrac{\sqrt3}2x+C_2e^x\sin\dfrac{\sqrt3}2x+\sin x}$

$y''-3y'+2y=e^x\sin x$

$\implies r^2-3r+2=(r-1)(r-2)=0\implies r=1,r=2$

$\implies y_c=C_1e^x+C_2e^{2x}$

Assume a solution of the form

$y_p=e^x(a\sin x+b\cos x)$

${y_p}'=e^x((a+b)\cos x+(a-b)\sin x)$

${y_p}''=2e^x(a\cos x-b\sin x)$

Substituting into the ODE gives

$2e^x(a\cos x-b\sin x)-3e^x((a+b)\cos x+(a-b)\sin x)+2e^x(a\sin x+b\cos x)=e^x\sin x$

$-e^x((a+b)\cos x+(a-b)\sin x)=e^x\sin x$

$\implies\begin{cases}-a-b=0\\-a+b=1\end{cases}\implies a=-\dfrac12,b=\dfrac12$

so the solution is

$\boxed{y(x)=C_1e^x+C_2e^{2x}-\dfrac{e^x}2(\sin x-\cos x)}$

$y''+y=x\cos(2x)$

$r^2+1=0\implies r=\pm i$

$\implies y_c=C_1\cos x+C_2\sin x$

Assume a solution of the form

$y_p=(ax+b)\cos(2x)+(cx+d)\sin(2x)$

${y_p}''=-4(ax+b-c)\cos(2x)-4(cx+a+d)\sin(2x)$

Substituting into the ODE gives

$(-4(ax+b-c)\cos(2x)-4(cx+a+d)\sin(2x))+((ax+b)\cos(2x)+(cx+d)\sin(2x))=x\cos(2x)$

$-(3ax+3b-4c)\cos(2x)-(3cx+3d+4a)\sin(2x)=x\cos(2x)$

$\implies\begin{cases}-3a=1\\-3b+4c=0\\-3c=0\\-4a-3d=0\end{cases}\implies a=-\dfrac13,b=c=0,d=\dfrac49$

so the solution is

$\boxed{y(x)=C_1\cos x+C_2\sin x-\dfrac13x\cos(2x)+\dfrac49\sin(2x)}$

7 0

3 years ago

F(x) = 7|x| awnser the question for some points

Eddi Din [679]

f(x) = 7|x|

if x= 1

then f(x) = 7

5 0

3 years ago

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13. Connie wants to paint one wall in her living room. Along the wall, she

erica [24]

Answer: Approximately 96 square feet

======================================================

Work Shown:

1 ft = 30 cm

1 ft = (5*6) cm

1 ft = 5*(6 cm)

1 ft = 5*(1 board width)

1 ft = 5 board widths

12*(1 ft) = 12*(5 board widths)

12 ft = 60 board widths

12 ft = 1 full wall length

The wall is 12 feet horizontally across and 8 feet tall, so its estimated area is 12*8 = 96 square feet approximately. This is approximate because of the fact we used the approximation of 1 ft = 30 cm.

7 0

3 years ago

Refer to a standard deck of playing cards. Assume 5 cards are randomly chosen from the deck. How many hands contain 4 aces?

Setler79 [48]

There would be 0.07923 probability to get 4 aces.

<h3>What is probability ?</h3>

Probability shows possibility to happen an event, it defines that an event will occur or not. The probability varies from 0 to 1.

Total number of cards in deck = 52

Total number of aces = 4

When 5 cards are chosen randomly,

The probability to get 4 aces

= 1/52+1/51+1/50+1/49+0

Since, at 5th time there will be no ace remains, so probability would be 0.

= 0.01923+0.01960+0.0200+0.0204

=0.07923

To know more about Probability on:

brainly.com/question/12478394

#SPJ1

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1 year ago