In order to calculate that, we need to divide it by 1/5 as follows:
60/100 / 1/5
We can re-write it as: 60/100 * 5 = 6/10 * 5 = 30/10 = 3
So, there are "3" 1/5ths in 60/100
Hope this helps!
Answer:
The actual SAT-M score marking the 98th percentile is 735.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

Find the actual SAT-M score marking the 98th percentile
This is X when Z has a pvalue of 0.98. So it is X when Z = 2.054. So




Answer:
what grade is this lol I don't know
The answer is: b - lies in quadrant II when graphed.
Explanation:
Any number less than zero is a negative number.
Example: -1
Any number greater than zero is a positive number.
Example: 1
(a, f(a))
(-1,1)
When these example points are graphed, they are placed in the second quadrant.
The answer is the top one.