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Delicious77 [7]
2 years ago
10

If possible, insert a digit to make the number divisible by 6. 13…0

Mathematics
1 answer:
Minchanka [31]2 years ago
4 0
Ok so to have a number divisible by 6, it needs to be divisible by 2 and 3. Because it ends in 0, it will always be divisible by 2. Now to be divisible by 3, the sum of all digits must be divisible by 3
Sk 1+3+? = something divisible by 3
? =2 in this scenario or 5 or 8
So possible numbers are 1320,1350,or 1380
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