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4 years ago

Can someone explain to do #51? Thank you!

Mathematics

2 answers:

kari74 [83]4 years ago

7 0

Answer:

11 3/8 ft

Step-by-step explanation:

convert mixed fractions then multiply them

13/4×7/2

11 3/8

Nuetrik [128]4 years ago

4 0

11 3/8 ft
Hope this helps

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Please help me i dont get either one of them i just need one of them. Please shiw steps. Thanks

pychu [463]

NO.4:X=38

NO.5:X=41

NO.6:X=24

5 0

3 years ago

Subtract seven over eight minus two over three

Stells [14]

Answer:

5/24

Step-by-step explanation:

hope it works for u good luck

4 0

3 years ago

PIT_PIT [208]

B : 4% of 780 is 31.20

4 0

3 years ago

The system of equations may have a unique solution, an infinite number of solutions, or no solution. Use matrices to find the ge

Leno4ka [110]

Answer:

Infinite number of solutions.

Step-by-step explanation:

We are given system of equations

$5x+4y+5z=-1$

$x+y+2z=1$

$2x+y-z=-3$

Firs we find determinant of system of equations

Let a matrix A= $\left[\begin{array}{ccc}5&4&5\\1&1&2\\2&1&-1\end{array}\right]$ and B= $\left[\begin{array}{ccc}-1\\1\\-3\end{array}\right]$

$\mid A\mid=\begin{vmatrix}5&4&5\\1&1&2\\2&1&-1\end{vmatrix}$

$\mid A\mid=5(-1-2)-4(-1-4)+5(1-2)=-15+20-5=0$

Determinant of given system of equation is zero therefore, the general solution of system of equation is many solution or no solution.

We are finding rank of matrix

Apply $R_1\rightarrow R_1-4R_2$ and $R_3\rightarrow R_3-2R_2$

$\left[\begin{array}{ccc}1&0&1\\1&1&2\\0&-1&-3\end{array}\right]$ : $\left[\begin{array}{ccc}-5\\1\\-5\end{array}\right]$

Apply $R_2\rightarrow R_2-R_1$

$\left[\begin{array}{ccc}1&0&1\\0&1&1\\0&-1&-3\end{array}\right]$ : $\left[\begin{array}{ccc}-5\\6\\-5\end{array}\right]$

Apply $R_3\rightarrow R_3+R_2$

$\left[\begin{array}{ccc}1&0&1\\0&1&1\\0&0&-2\end{array}\right]$ : $\left[\begin{array}{ccc}-5\\6\\1\end{array}\right]$

Apply $R_3\rightarrow- \frac{1}{2}$ and $R_2\rightarrow R_2-R_3$

$\left[\begin{array}{ccc}1&0&1\\0&1&0\\0&0&1\end{array}\right]$ : $\left[\begin{array}{ccc}-5\\\frac{13}{2}\\-\frac{1}{2}\end{array}\right]$

Apply $R_1\rightarrow R_1-R_3$

$\left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\end{array}\right]$ : $\left[\begin{array}{ccc}-\frac{9}{2}\\\frac{13}{2}\\-\frac{1}{2}\end{array}\right]$

Rank of matrix A and B are equal.Therefore, matrix A has infinite number of solutions.

Therefore, rank of matrix is equal to rank of B.

4 0

4 years ago

Pls help me first get 10 you know

Luba_88 [7]

Option D, 63 cm

Explanation:

The scale of model is of local park is

This means that each dimension of the model is 21 times smaller than the actual park (to be developed in future)

Given -

Depth of the pond centi meter

Depth of the real pond will be 21 times of the depth of the model.

Thus , real pond's depth is equal to

Hence, option D is correct

7 0

3 years ago