4x + 4 ( 3x - 7)
distribute the 4 into (3x-7)
4x + 12x -28
16x - 28 = 22x -65
answer choice D
The correct answer is like terms. Hope this helps.
Answer:
(x, y)→(x − 9, y − 3)
Step-by-step explanation:
We have given Hexagon DEFGHI is translated on the coordinate plane to create hexagon D'E'F'G'H'I':
We write the translation one by one:
D (3, 5)
D' (-6, 2)
that translates to: (x - 9, y - 3), because that is for passing from D to D':
(3 - 9, 5 - 3) = (-6, 2)
Now for E (7,5)
E' (-2,2)
that translates to: (x - 9, y - 3), because that is for passing from E to E':
(7 - 9, 5 - 3) = (-2, 2)
Now for F(8,2)
F' (-1, -1)
that translates to: (x - 9, y - 3), because that is for passing from F to F':
(8 - 9, 2 - 3) = (-1, -1)
therefore if it is true for D and D', E and E', F and F' then it has to be true for all others for the rule to be true, so the rule represents the translation of hexagon DEFGHI to hexagon D'E'F'G'H'I' is (x, y)→(x − 9, y − 3) ....
Answer:
Step-by-step explanation:
Previous concepts
The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.
The variance of a random variable X represent the spread of the possible values of the variable. The variance of X is written as Var(X).
Solution to the problem
Since the warranty on a machine specifies that it will be replaced at failure or age 4 and the distribution for X is defined between 0 and 5 then if we define the random variable Y ="the age of the machine at the time of replacement" we know that the values for Y needs to be between 0 and 4 or between 4 and and we can define the following density function:
for other case
Now we can apply the definition of expected value and we have this:
And for the second moment we have:
And the variance would be given by:
Answer:
negative
Step-by-step explanation: