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rewona [7]
4 years ago
14

The Department of Transportation would like to test the hypothesis that the average age of cars on the road is less than 12 year

s. A random sample of 45 cars had an average age of 10.6 years. It is believed that the population standard deviation for the age of cars is 4.1 years. The Department of Transportation would like to set α = 0.05. The conclusion for this hypothesis test would be that because the test statistic is ______________________________________.
Mathematics
1 answer:
puteri [66]4 years ago
8 0

Answer:

z=\frac{10.6-12}{\frac{4.1}{\sqrt{45}}}=-2.29  

Step-by-step explanation:

information given

\bar X=10.6 represent the sample mean  

\sigma=4.1 represent the population standard deviation

n=45 sample size  

\mu_o =12 represent the value that we want to test  

\alpha=0.05 represent the significance level for the hypothesis test.  

z would represent the statistic

p_v represent the p value for the test

Hypothesis to test

We want to test if the true mean is less than 12, the system of hypothesis would be:  

Null hypothesis:\mu \geq 10  

Alternative hypothesis:\mu < 10  

The statistic is given by:

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)  

Replacing the info given we got:

We can replace in formula (1) the info given like this:  

z=\frac{10.6-12}{\frac{4.1}{\sqrt{45}}}=-2.29  

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Answer:

We can not solve for a unique cost for each soldier.

Step-by-step explanation:

Let x be the daily cost for legionaries and y be the daily cost for archers.  

Upon using our given information we will get a system of linear equations as:

3x+3y=10...(1)

x+y=3...(2)

Now we will solve for x from our 2nd equation,

x = 3-y

Now we will substitute this value in our 1st equation.

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9-3y+3y=10

We can see that -3y cancels out with 3y  and 9 is not equal to 10. So this is an unsolvable system. Therefore, we can not find a unique cost for each soldier.


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Step-by-step explanation:

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Step-by-step explanation:

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Find the values of the sine, cosine, and tangent for ZA.<br><br> (TOP OF TRIANGLE IS (A))
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\bigstar\:{\underline{\sf{In\:right\:angled\:triangle\:ABC\::}}}\\\\

  • AC = 7 m
  • BC = 4 m

⠀⠀⠀

\bf{\dag}\:{\underline{\frak{By\:using\:Pythagoras\: Theorem,}}}\\\\

\star\:{\underline{\boxed{\frak{\purple{(Hypotenus)^2 = (Perpendicular)^2 + (Base)^2}}}}}\\\\\\ :\implies\sf (AB)^2 = (AC)^2 + (BC)^2\\\\\\ :\implies\sf (AB)^2 = (AB)^2 = (7)^2 = (4)^2\\\\\\ :\implies\sf (AB)^2 = 49 + 16\\\\\\ :\implies\sf (AB)^2 = 65\\\\\\ :\implies{\underline{\boxed{\pmb{\frak{AB = \sqrt{65}}}}}}\:\bigstar\\\\

⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━━━

☆ Now Let's find value of sin A, cos A and tan A,

⠀⠀⠀

  • sin A = Perpendicular/Hypotenus = \sf \dfrac{4}{\sqrt{65}} \times \dfrac{\sqrt{65}}{\sqrt{65}} = \pink{\dfrac{4 \sqrt{65}}{65}}

⠀⠀⠀

  • cos A = Base/Hypotenus = \sf \dfrac{7}{\sqrt{65}} \times \dfrac{\sqrt{65}}{\sqrt{65}} = \pink{\dfrac{7 \sqrt{65}}{65}}

⠀⠀⠀

  • tan A = Perpendicular/Base = {\sf{\pink{\dfrac{4}{7}}}}

⠀⠀⠀

\therefore\:{\underline{\sf{Hence,\: {\pmb{Option\:A)}}\:{\sf{is\:correct}}.}}}

4 0
3 years ago
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