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Aleks [24]
3 years ago
14

How many times greater is the value of 5 in 3,590 than the value of 5 in 359 ?

Mathematics
1 answer:
Tresset [83]3 years ago
4 0

Answer:

10 times greater is the value of 5 in 3,590 than the value of 5 in 359.

Step-by-step explanation:

To find : How many times greater is the value of 5 in 3,590 than the value of 5 in 359 ?

Solution :

The place value stem is

Thousand     Hundred     Tens    Ones

  1000               100            10         1

The value of 5 in 3,590 is at hundred place

So, 5\times 100=500

The value of 5 in 359 is at tens place

So, 5\times 10=50

Number of time greater is the value of 5 in 3,590 than the value of 5 in 359 is given by,

n=\frac{500}{50}

n=10

Therefore, 10 times greater is the value of 5 in 3,590 than the value of 5 in 359.

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Jared is creating a flower garden in the shape of a triangle. which could be the dimensions of the garden in feet
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Answer:

B- 3 by 7 by 9 is the only right answer.

Step-by-step explanation:

What is a triangle?

A triangle is a polygon with three edges and three vertices. It is one of the basic shapes in geometry. A triangle with vertices A, B, and C is denoted.

Basic rule:

A triangle must be tri-sided, means it must have three sides which is only possible if the sum of the smaller two sides is greater than the third side. Otherwise, a triangle is not physically possible.

A- 2+3 = 5 hence not a triangle.

B- 3+7 > 9 hence a triangle.

C- 4+5 < 9.5 hence not a triangle.

D- 5+6 < 12 hence not a triangle.

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3 years ago
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Seamus plays outside for five and five sixths hours every week. He has already played outside for four and three sixths hours. H
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2 years ago
If $10,000 is invested at an annual rate of 11%, compounded quarterly, find the value of the investment after the given number o
lana [24]

Answer:

a) A\simeq17204.28

b) A\simeq29598.74

c)A\simeq50922.51

Step-by-step explanation:

The amount formula in compound interest is:

A=P(1+\frac{r}{n} )^{nt}

where:

P = principal amount

r = annual interest

n = number of compounding periods

t = number of years

We already know that:

P = $10000

r = 11\% = \frac{11\%}{100\%}=0.11

n = 4 (quarterly in a year)

a ) t = 5 years

A=10000(1+\frac{0.11}{4} )^{(4)(5)}\\\\A=10000(1+\frac{0.11}{4} )^{20}\\\\A=17204.28431\\\\A\simeq17204.28

b) t = 10 years

A=10000(1+\frac{0.11}{4} )^{(4)(10)}\\\\A=10000(1+\frac{0.11}{4} )^{40}\\\\A=29598.73987\\\\A\simeq29598.74

c) t = 15 years

A=10000(1+\frac{0.11}{4} )^{(4)(15)}\\\\A=10000(1+\frac{0.11}{4} )^{60}\\\\A=50922.51361\\\\A\simeq50922.51

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2 years ago
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