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3 years ago

Evaluate this question

Mathematics

1 answer:

cestrela7 [59]3 years ago

3 0

Answer:

Step-by-step explanation:

$\bigg( \frac{16}{49} \bigg)^{ - \frac{3}{2} } \\ \\ = \bigg( \frac{49}{16} \bigg)^{ \frac{3}{2} } \\ \\ = \bigg( \frac{ {7}^{2} }{ {4}^{2} } \bigg)^{ \frac{3}{2} } \\ \\ = \bigg( \frac{ {7}}{ {4} } \bigg)^{ \frac{2 \times 3}{2} } \\ \\ = \bigg( \frac{ {7}}{ {4} } \bigg)^{ 3} \\ \\ = \frac{343}{64} \\$

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Helga [31]

Answer:

Step-by-step explanation:

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3 years ago

Simplify. Your answer should contain only positive exponents with no fractional exponents in the denominator.

mart [117]

Answer:

$\dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}$ .

Step-by-step explanation:

The given expression is

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We need to simplify the expression such that answer should contain only positive exponents with no fractional exponents in the denominator.

Using properties of exponents, we get

$\dfrac{3}{4\cdot 3}\cdot \dfrac{y^{\frac{1}{4}}}{x^{-\frac{2}{3}}y^{\frac{3}{2}+\frac{1}{2}}}$ $[\because a^ma^n=a^{m+n}]$

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$\dfrac{1}{4}\cdot \dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{y^{2}}$ $[\because a^{-n}=\dfrac{1}{a^n}]$

$\dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}$

We can not simplify further because on further simplification we get negative exponents in numerator or fractional exponents in the denominator.

Therefore, the required expression is $\dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}$ .

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3 years ago

A hot-air balloon is moving on a bearing of 2450 at 31mph. A wind is blowing with the bearing of 2600 at 23mph. Find the compone

Alborosie

Answer:

$V=(54i) \ mph$

Step-by-step explanation:

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Answer:

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180÷18=10

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2 years ago

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