Line segment XY begins at (-6,4) and ends at (-2,4); XY is reflected over the x-axis and translated left 3 units to form line segment X'Y' which has a length of 4 units.

<h3>What is a system of equations?</h3>

A system of equations is two or more equations that can be solved to get a unique solution. the power of the equation must be in one degree.

Line segment XY begins at (-6,4) and ends at (-2,4). Hence:

$XY = \sqrt{(4-4)^2 + (-2 +6)^2} \\\\XY = \sqrt{0+16} \\\\XY = \sqrt{16} \\\\XY = 4$

XY is reflected over the x-axis and translated left 3 units to form line segment X'Y'. Hence:

XY = X'Y' = 4 units

Line segment XY begins at (-6,4) and ends at (-2,4); XY is reflected over the x-axis and translated left 3 units to form line segment X'Y' which has a length of 4 units.

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5 0

2 years ago

When an amount of heat Q (in kcal) is added to a unit mass (kg) of a

lisov135 [29]

Answer:

The change in temperature per minute for the sample, dT/dt is 71. $\overline {6}$ °C/min

Step-by-step explanation:

The given parameters of the question are;

The specific heat capacity for glass, dQ/dT = 0.18 (kcal/°C)

The heat transfer rate for 1 kg of glass at 20.0 °C, dQ/dt = 12.9 kcal/min

Given that both dQ/dT and dQ/dt are known, we have;

$\dfrac{dQ}{dT} = 0.18 \, (kcal/ ^{\circ} C)$

$\dfrac{dQ}{dt} = 12.9 \, (kcal/ min)$

Therefore, we get;

$\dfrac{\dfrac{dQ}{dt} }{\dfrac{dQ}{dT} } = {\dfrac{dQ}{dt} } \times \dfrac{dT}{dQ} = \dfrac{dT}{dt}$

$\dfrac{dT}{dt} = \dfrac{\dfrac{dQ}{dt} }{\dfrac{dQ}{dT} } = \dfrac{12.9 \, kcal / min }{0.18 \, kcal/ ^{\circ} C } = 71.\overline 6 \, ^{\circ } C/min$

For the sample, we have the change in temperature per minute, dT/dt, presented as follows;

$\dfrac{dT}{dt} = 71.\overline 6 \, ^{\circ } C/min$

8 0

3 years ago

To encourage bulk buying a company reduces the list price of $9000 per unit by seven cents times the number of units bought writ

Misha Larkins [42]

Answer:

R(x) = 8999.93x

Step-by-step explanation:

The original price is $9000 per unit. The unit is x, so if you buy x units, you pay 9000x.

The original price function is

R(x) = 9000x

The discount is 7 cents per unit bought, so if you buy x units, the discount is 9x in cents, or 0.09x in dollars. This discount is subtracted from the original price, so the discounted price is

R(x) = 9000x - 0.07x

R(x) = 8999.93x

Answer: R(x) = 8999.93x

7 0

3 years ago

What is the value of the expression shown below?

lesya692 [45]

(3/5)^2 + 4 × 3 - 2
9/25 + 12 - 2
9/25 + 10
It would be 10 and 9 over 25

4 0

3 years ago

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