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beks73 [17]
3 years ago
11

What would a good digital citizen do in the following situation? Nick sees that his classmate left her email account open on a s

chool computer by mistake. Nick decides to _____.
Question 1 options:

send an email from her account to a friend


log out of her email and let her know that he closed it for her


not do anything and let someone else deal with it


delete all of her emails
Computers and Technology
1 answer:
Inessa [10]3 years ago
3 0
1234567898765432123456789876543212345678987654321
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Jane Estroisch works as a manager in a multidomestic firm. She focuses on the long-term questions facing the organization such a
navik [9.2K]

Answer:

b

Explanation:

Tactical. Perhaps she needs yo keep in touch with the board of directors in order to make an strategic planning.

3 0
3 years ago
Knowledge of html and css is considered essential for the job of a(n _______.
7nadin3 [17]
<span>Knowledge of html and css is considered essential for the job of a web-designer. Html and css are useful if you want to build an informational web-site or landing page. Html is used for page structure and basic style. Css used for advanced styles, it helps you to make your web-site look prettier. If you want to make the advanced functions on your web-site, you should use javascript or php.</span>
4 0
3 years ago
Assignment Background Video games have become an outlet for artists to express their creative ideas and imaginations and a great
Sphinxa [80]

Answer:

Code

import csv

def open_file():

try:

fname=input("Enter the filename to open (xxx.yyy): ")

fp=open(fname,encoding='utf-8')

return fp

except FileNotFoundError:

print("File not found! Please Enter correct filename with extension")

return open_file()

def read_file(fp):

fields = []

rows = []

csvreader = list(csv.reader(fp))

# skiped 1 row because it contains field name

fields = csvreader[0]

D1={}

D2={}

D3={}

# accessing the data of csv file

for line in csvreader[1:]:

name = line[0].lower().strip()

platform = line[1].lower().strip()

if line[2]!='N/A':

year = int(line[2])

else:

year=line[2]

genre = line[3].lower().strip()

publisher = line[4].lower().strip()

na_sales = float(line[5])

eur_sales = float(line[6])

jpn_sales = float(line[7])

other_sales = float(line[8])

global_sales=(na_sales+eur_sales+jpn_sales+other_sales)*1000000

if name not in D1:

D1[name]=[]

D1[name].append((name, platform, year, genre, publisher,global_sales))

if genre not in D2:

D2[genre]=[]

D2[genre].append((genre, year, na_sales, eur_sales,jpn_sales, other_sales, global_sales))

if publisher not in D3:

D3[publisher]=[]

D3[publisher].append((publisher, name, year, na_sales,eur_sales, jpn_sales, other_sales, global_sales))

# sorting

temp={}

# sorting keys

for Keys in sorted (D1) :

ls=D1[Keys]

ls=sorted(ls,key=lambda x: x[-1]) # sorting values

temp[Keys]=ls

D1=temp.copy()

temp={}

# sorting keys

for Keys in sorted (D2) :

ls=D2[Keys]

ls=sorted(ls,key=lambda x: x[-1]) # sorting values

temp[Keys]=ls

D2=temp.copy()

temp={}

# sorting keys

for Keys in sorted (D3) :

ls=D3[Keys]

ls=sorted(ls,key=lambda x: x[-1]) # sorting values

temp[Keys]=ls

D3=temp.copy()

return D1,D2,D3

 

def main():

fp=open_file()

D1,D2,D3=read_file(fp)

# displaying the row_count in dictionaries

cnt=0

for d in D1:

cnt+=1

print(cnt)

print("\n\n=============================================\n\n")

cnt=0

for d in D2:

cnt+=1

print(cnt)

print("\n\n=============================================\n\n")

cnt=0

for d in D3:

cnt+=1

print(cnt)

print("\n\n=============================================\n\n")

 

 

if __name__=="__main__":

main()

Explanation:

see code and see output attached

7 0
3 years ago
QUESTION 6 Which of the following is a class A IPv4 address? a. 118.20.210.254 b. 183.16.17.30 c. 215.16.17.30 d. 255.255.0.0
shepuryov [24]

Answer:

a. 118.20.210.254

Explanation:

Here are the few characteristics of Class A:

First bit of the first octet of class A is 0.

This class has 8 bits for network and 24 bits for hosts.

The default sub-net mask for class A IP address is 255.0.0.0

Lets see if the first bit of first octet of 118.20.210.254 address is 0.

118 in binary (8 bits) can be represented as : 1110110

To complete 8 bits add a 0 to the left.

01110110

First bit of the first octet of class A is 0 So this is class A address.

For option b the first octet is : 183 in the form of bits = 10110111 So it is not class A address

For option c the first octet is 215 in the form of bits = 11010111 So it is not class A address

For option d the first octet is 255 in the form of bits = 11111111. The first bit of first octet is not 0 so it is also not class A address.

3 0
3 years ago
You are most likely to automatically encode information about
Orlov [11]

Answer:

You are most likely to automatically encode information about the sequence of your day's events.

5 0
3 years ago
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