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ch4aika [34]
1 year ago
9

Substance A has a density of 0.98 g/mL. Substance B has a density of 1.13 g/mL. Water has a density of approximately 1.0 g/mL. W

hich substance will float in water?
Chemistry
1 answer:
Dima020 [189]1 year ago
6 0

Answer:

Substance A

Explanation:

A substance that has a higher density than water will sink in water, while that with a lower density than water will float on water.

Substance A, with a lower density of 0.98 g/ml as compared to that of water (1.0 g/ml) will thus float in water.

<u>What is density?</u>

Density is defined as the amount of substance per unit volume. The concept of density is usually one of comparison, which means whether a substance with a particular density value will sink or float will depend on the fluid's density it is placed in.

A higher density means that the substance has a higher mass per unit volume, so it's "heavier" and will thus sink.

<u>Formula</u>

\boxed{\text{Density}=\frac{\text{mass}}{\text{volume} }}

To learn more about density, check out: brainly.com/question/9149928

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If 50 ml of 0.235 M NaCl solution is diluted to 200.0 ml what is the concentration of the diluted solution
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This is a straightforward dilution calculation that can be done using the equation

M_1V_1=M_2V_2

where <em>M</em>₁ and <em>M</em>₂ are the initial and final (or undiluted and diluted) molar concentrations of the solution, respectively, and <em>V</em>₁ and <em>V</em>₂ are the initial and final (or undiluted and diluted) volumes of the solution, respectively.

Here, we have the initial concentration (<em>M</em>₁) and the initial (<em>V</em>₁) and final (<em>V</em>₂) volumes, and we want to find the final concentration (<em>M</em>₂), or the concentration of the solution after dilution. So, we can rearrange our equation to solve for <em>M</em>₂:

M_2=\frac{M_1V_1}{V_2}.

Substituting in our values, we get

\[M_2=\frac{\left ( 50 \text{ mL} \right )\left ( 0.235 \text{ M} \right )}{\left ( 200.0 \text{ mL} \right )}= 0.05875 \text{ M}\].

So the concentration of the diluted solution is 0.05875 M. You can round that value if necessary according to the appropriate number of sig figs. Note that we don't have to convert our volumes from mL to L since their conversion factors would cancel out anyway; what's important is the ratio of the volumes, which would be the same whether they're presented in milliliters or liters.

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