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zzz [600]
1 year ago
7

Enter the range of values for x using the picture shown

Mathematics
1 answer:
yarga [219]1 year ago
8 0

We are asked to find a range for x. Let's start by finding the maximum value. We know, by definition, that a side opposite a larger angle has a longer length. For example, if you think about a right triangle, the hypotenuse (the longest side) is always opposite of the right angle (the largest angle). We are given two side lengths: 23 is opposite of 42 degrees, and 21 is opposite of 3x + 15. Because 42 is opposite the longer side, 42 degrees is a larger angle than 3x + 15. We can set up the inequality and solve for x:

\begin{gathered} 3x+15

Now, let's look at the minimum value. We know that the angle definitely has to be larger than 0. So, we can set up that inequality and solve for x:

\begin{gathered} 3x+15>0 \\ 3x>-15 \\ x>-5 \end{gathered}

Now, we have our final range: -5 < x < 9

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Are the ratios 2:1 and 9:5 equivalent?
puteri [66]

Answer:

no

Step-by-step explanation:

if we put the ratios as fractions, we would get 2/1, or just 2, and 1 4/5. these are not equivalent, so the ratios are not equivalent either.

3 0
3 years ago
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Exercise 6.22 provides data on sleep deprivation rates of Californians and Oregonians. The proportion of California residents wh
kherson [118]

Answer:

a. The alternative hypothesis H₀: p'₁ ≠ p'₂ is accepted

b. Type I error

Step-by-step explanation:

Proportion of California residents who reported insufficient rest = 8.0%

Proportion of Oregon  residents who reported insufficient rest = 8.8%

p'₁ = 0.08 * 11545 =923.6

p'₂ = 0.088 * 4691=412.81

σ₁ = \sqrt{n*p_1*q_1}  = \sqrt{n*p_1*(1-p_1)} = \sqrt{11545*0.08*(1-0.08)} = 29.15

σ₂ = \sqrt{n*p_2*q_2}  = \sqrt{n*p_2*(1-p_2)}= \sqrt{4691*0.088*(1-0.088)} = 19.40

Samples size of California residents n₁ = 11,545

Samples size of Oregon residents n₂ = 4,691

Hypothesis can be constructed thus

Let our null hypothesis be H ₀: p'₁ = p'₂

and alternative hypothesis H ₐ: p'₁ ≠ p'₂

Then we have  

z =\frac{(p'_1 -p'_2)-(\mu_1-\mu_2)}{\sqrt{\frac{\sigma^2_1}{n_1}+\frac{\sigma^2_2}{n_2} } }

The test statistics can be computed by

     

t₀ = \sqrt{\frac{n_1n_2(n_1+n_2-2)}{n_1+n_2} } *\frac{p_1'-p_2'}{\sqrt{(n_1-1)\sigma_1^2+(n_2-1)\sigma_2^2} } =      1104.83

c from tables is   P(T ≤ c) = 1 - α where α = 5% and c = 1.65

since t₀ ≥ c then then the hypothesis is rejected which means the alternative hypothesis is rejected

b. Type I error, rejecting a true hypothesis

5 0
3 years ago
The ballpark made a total of $15,000 from ticket sales at Wednesday's game. The ballpark charges $20 for each adult ticket and $
kvasek [131]
Assume that the number of adult tickets is a and the number of child tickets is c.

We are given that the adult ticket is sold for 20$, the child ticket is sold for 10$ and that the total is $15,000. This means that:
20a + 10c = 15,000 ..........> equation I

We are also given that number of child tickets is 3 times that of adult's. This means that:
c = 3a .........> equation II

Substitute with equation II in equation I to get a as follows:
20a + 10c = 15,000
20a + 10(3a) = 15,000
20a + 30a = 15,000
50a = 15,000
a = 300 tickets

Substitute with the value of a in equation II to get c as follows:
c = 3a
c = 3(300)
c = 900 tickets

Based on the above calculations,
number of child tickets = 900 ticket
number of adult tickets = 300 ticket
3 0
3 years ago
A cabinetmaker gets paid monthly at a rate of $350 for each cabinet she completes. Last month, she made 6 cabinets and got halfw
lys-0071 [83]

$2,100 since she only finished 6 cabinets. I hope this helps you!

6 0
3 years ago
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Please help am stuck on this
Marina86 [1]

Answer:

-3,-2,-1,0,1,2,3,4,5

8 0
3 years ago
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