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BaLLatris [955]
1 year ago
8

How far can the center of the box be from the end of the table before the board begins to tilt?

Mathematics
1 answer:
Vesnalui [34]1 year ago
7 0

in case of box start being tilt,

box should be half out the table,

<h3>What is COM?</h3>

The Center of Mass of an object or system of objects is a location that is specified in relation to those objects. The Center of Mass of a system is the location where all of its components are on average when they are all weighted in accordance with their masses. The centroid is where basic stiff objects with homogenous density have their centers of mass. Sometimes an object's Center of Mass might not be directly over it. The Center of Mass would be on the Center in the event of a uniform disc, but there would be no material in the case of a ring where the Center of Mass would be on the Center.

The Centre of Mass for intrinsic shapes can be defined as the position where the sum of all of its weighted position vectors of all the parts equals zero.

In this we can use the Center of Mass concept,

As it will leave table when normal is not acting from the table at the center of mass.

So, as in case of box measuring ( x, y, z ) the center of mass from any point of the box is \sqrt{x^{2} +y^{2}+ z^{2}  }

So in case of box start being tilt,

box should be half out the table,

So that COM must be just outside the table

To learn more about Position vector , visit,

brainly.com/question/1563531

#SPJ1

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hjlf

Answer:

f+g(2)=10

f-g(4)=-4

F/G(2)= 7/3

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Step-by-step explanation:

1. (f+g)=2x+3+x^2-1 2(2)+2=10

2. (f-g)=(2x+3)-(x^2-1)=-x^2+2x+4= -16+8+4=-4

3. f/g= 2x+3/x^2-1 4+3/3= 7/3

4. f*g= (2x+3)(x^2-1)= 2x^3+3x^2-2x-3= 2(1)^3-2(1)+3(1)^2-3=0

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Step-by-step explanation:

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