<span>In 10 years, you will have $31,049.30</span>
<span> tan(x)/ cos(x)-sec(x)
tanx/(cosx-1/cosx)
tanx/cos^2x-1)--------------------1-sin^2x=cos^2x
-tanx/sin^2x
-(sinx/cosx)/sin^2x
-1/sinxcosx
multiply 2/2
-2/2sinxcosx-------------sin2x=2sincosx
-2/sin2x------------------1/sinx=cosecx
-2cosec2x</span>
Hello,
ln(y)=ln(x^(ln(x))=ln(x)*ln(x)=(ln(x))²
(ln(y))'=2ln(x)*1/x
(1/y)*y'=2ln(x) / x
y'=(2 ln(x) * x^(ln(x)) ) /x
I think it’s A I’m sorry if I am wrong so I am pretty sure it’s A
1+tan^2(A) = sec^2(A) [Pythagorean Identities]
tan^2(A)cot(A) = tan(A)[tan(A)cot(A)] = tan(A)[1] = tan(A)
*see photo for complete solution*