All categories

3 years ago

Is (4,7) a solution of the systems of inequalities (2x-y>-1) )5x-3y <1) ?

Mathematics

1 answer:

svp [43]3 years ago

8 0

The ordered pair is a solution to the system.
2(4) - 7 = 1
1 > -1 YES

5(4) -3(7) = 20-21 = -1
-1 < 1 YES

You might be interested in

How would I be able to get the step by step prosses of this and the answer of y?

Daniel [21]

Answer:

y = 3

Step-by-step explanation:

-7 = -4y + 5

Subtract 5 from both sides to isolate variable y:

-7 - 5 = -4y + 5 - 5

-12 = -4y + 0

-12 = -4y

Divide both sides by -4 to isolate variable y:

-12 ÷ -4 = -4y ÷ -4

(Negative ÷ Negative = Positive)

3 = 1y

3 = y

Check your work:

-7 = -4(3) + 5

Use PEMDAS:

-7 = -12 + 5

-7 = -7

Correct!

6 0

3 years ago

23. A football match ended at 16 35 hours. The duration of the match was 1 hour 45 minutes. What time did the football match sta

Arturiano [62]

The match started at 1450 hours.

3 0

1 year ago

Which is the equation of a circle whose center is at the origin and that passes through the point (3, 5)?

xxTIMURxx [149]

Answer:

x² + y² = 34

Formula:

(x - h)² + (y - k)² = r² where (h, k) is the center

<u>Here find the radius using distance formula</u>: → origin : (0, 0)

√(x2-x1)²+(y2-y1)²

√(3-0)²+(5-0)²

√9+25

√34

<u>Thus the equation of circle</u>:

(x - 0)² + (y - 0)² = (√34)²

(x - 0)² + (y - 0)² = 34

x² + y² = 34

7 0

3 years ago

Read 2 more answers

The operator of a pumping station has observed that demand for water during early afternoon hours has an approximately exponenti

melomori [17]

Answer:

a) 0.1496 = 14.96% probability that the demand will exceed 190 cfs during the early afternoon on a randomly selected day.

b) Capacity of 252.6 cubic feet per second

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

$f(x) = \mu e^{-\mu x}$

In which $\mu = \frac{1}{m}$ is the decay parameter.

The probability that x is lower or equal to a is given by:

$P(X \leq x) = \int\limits^a_0 {f(x)} \, dx$

Which has the following solution:

$P(X \leq x) = 1 - e^{-\mu x}$

The probability of finding a value higher than x is:

$P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}$

The operator of a pumping station has observed that demand for water during early afternoon hours has an approximately exponential distribution with mean 100 cfs (cubic feet per second).

This means that $m = 100, \mu = \frac{1}{100} = 0.01$

(a) Find the probability that the demand will exceed 190 cfs during the early afternoon on a randomly selected day. (Round your answer to four decimal places.)

We have that:

$P(X > x) = e^{-\mu x}$

This is P(X > 190). So

$P(X > 190) = e^{-0.01*190} = 0.1496$

0.1496 = 14.96% probability that the demand will exceed 190 cfs during the early afternoon on a randomly selected day.

(b) What water-pumping capacity, in cubic feet per second, should the station maintain during early afternoons so that the probability that demand will exceed capacity on a randomly selected day is only 0.08?

This is x for which:

$P(X > x) = 0.08$

$e^{-0.01x} = 0.08$

$\ln{e^{-0.01x}} = \ln{0.08}$

$-0.01x = \ln{0.08}$

$x = -\frac{\ln{0.08}}{0.01}$

$x = 252.6$

Capacity of 252.6 cubic feet per second

5 0

3 years ago

Plz help with any of them it’s a emergency

devlian [24]

To find a perimeter, add all sides together:

9) 12 + 12 + 8 + 8 = 20 + 20 = 40 in
10) 3 + 3 + 3 + 3 = 6 + 6 = 12 cm

To find area, multiply length and width, or base and height:

11) 3 x 6 = 18
12) 10 x 30 = 300 ft
13) 12 x 12 = 144 cm
14) 7 x 4 = 28 m

15)
Perimeter: 2(2) + 2(16) = 4 + 32 = 36
Area: 1 x 16 = 16

hope this helps

7 0

3 years ago

Read 2 more answers