Question

Be sure to simplify your answer. I really need help I will give the brainiest!!

Answer 1

Answer:

$h(-1)=-\dfrac{\boxed{2}}{\boxed{3}}$

Step-by-step explanation:

Given function:

$h(x)=\dfrac{2x-6}{4x^2+8}$

To find h(-1), substitute x = -1 into the given function:

$\begin{aligned}\implies h(-1)&=\dfrac{2(-1)-6}{4(-1)^2+8}\\\\&=\dfrac{-2-6}{4(1)+8}\\\\&=\dfrac{-2-6}{4+8}\\\\&=\dfrac{-8}{12}\\\\&=\dfrac{-8 \div 4}{12 \div 4}\\\\&=-\dfrac{2}{3}\end{aligned}$

Answer 2

Answer:

${ \sf{h(x) = \frac{2x - 6}{ {4x}^{2} + 8 } }}$

h(-1) implies that x = -1; therefore

${ \sf{h( - 1) = \frac{2( - 1) - 6}{4 {( - 1)}^{2} + 8 } }} \\ \\ { \sf{h( - 1) = \frac{ - 2 - 6}{4 + 8} }} \\ \\ { \sf{h( - 1) = \frac{ - 8}{12} }} \\ \\ { \boxed{ \sf{ \: h( - 1) = - \frac{2}{3} }}}$