The line segment that has the same measure as TQ is TR
<h3>How to determine the
line segment that has the
same measure as TQ?</h3>
The figure that completes the question is added as an attachment
From the figure, we have the following properties:
- Lines TQ and TR are congruent
- Lines QS and RS are congruent
The above implies that the line segment that has the same measure as TQ is TR
Hence, the line segment that has the same measure as TQ is TR
Read more about line segments at:
brainly.com/question/2437195
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Let
![a_n](https://tex.z-dn.net/?f=a_n)
be the n'th term of the sequence.
so
![a_1](https://tex.z-dn.net/?f=a_1)
is the first term,
![a_2](https://tex.z-dn.net/?f=a_2)
the second term and so on...
In a geometric sequence with
![a_1=c](https://tex.z-dn.net/?f=a_1%3Dc)
, and common ratio r, the terms are as follows:
![a_1=c](https://tex.z-dn.net/?f=a_1%3Dc)
![a_2=cr](https://tex.z-dn.net/?f=a_2%3Dcr)
![a_3=c r^{2}](https://tex.z-dn.net/?f=a_3%3Dc%20r%5E%7B2%7D%20)
![a_4=c r^{3}](https://tex.z-dn.net/?f=a_4%3Dc%20r%5E%7B3%7D%20)
.
.
that is, each term is its previous term times the common ratio r.
In our example
![a_2=cr=20](https://tex.z-dn.net/?f=a_2%3Dcr%3D20)
and
![a_4=c r^{3}=11.25](https://tex.z-dn.net/?f=a_4%3Dc%20r%5E%7B3%7D%3D11.25%20)
![\frac{a_2}{a_4}= \frac{cr}{c r^{3}}= \frac{1}{ r^{2}}= \frac{20}{11.25}= 1.778](https://tex.z-dn.net/?f=%20%5Cfrac%7Ba_2%7D%7Ba_4%7D%3D%20%5Cfrac%7Bcr%7D%7Bc%20r%5E%7B3%7D%7D%3D%20%5Cfrac%7B1%7D%7B%20r%5E%7B2%7D%7D%3D%20%5Cfrac%7B20%7D%7B11.25%7D%3D%201.778%20)
so
![r^{2} =1/1.778=0.56](https://tex.z-dn.net/?f=r%5E%7B2%7D%20%3D1%2F1.778%3D0.56)
![r= \sqrt{0.56}= 0.75](https://tex.z-dn.net/?f=r%3D%20%5Csqrt%7B0.56%7D%3D%200.75)
Answer: r=0.75
Answer:
0.30%
Step-by-step explanation:
Answer:
Multiplication
Step-by-step explanation:
Follow PEMDAS, so first you would sub in the 5 then work in the parentheses so you would multiply the 5