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galina1969 [7]
2 years ago
13

What is the vertex of the graph of y = –x2? (–1, 0) (0, –1) (0, 0) (1, 1)

Mathematics
1 answer:
mestny [16]2 years ago
4 0

Answer:

The vertex is (0, 0).

Step-by-step explanation:

Check out the parent function:  y = x^2.  The graph is a parabola whose vertex is (0, 0) and which opens upward.

Then y = -x^2 is the same but opens downward.  The vertex is (0, 0).

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A and B are postive integers such that 1/a + 1/b +1/ab = 1. Find ab
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=> a + b + 1 = ab

⇔ a + b + 1 - ab = 0

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because a and b are postive integers => (b - 1) and (1 - a) also are integers

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because (b -1).(1-a) = -2 => we have the table:

b - 1        -1             1              2             -2

1 - a         2            -2            -1              1

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b              0            2             3              -1

a.b            0           6             6               0

because a and b  are postive integers

=> (a;b) = (3;2) or (a;b) = (2;3)

=> ab = 6

Step-by-step explanation:

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