Question

carl's television stopped working just before the big game and he did not have enough money to purchase another television. he knew that a motel near his workplace had recently purchased very nice televisions for all of the rooms in the hotel. these television sets cost $1000.00 each, but the fair market value of the used television sets is only $200.00. carl goes to the motel at 5 pm, opens the unlocked door of one of the rooms (which was rented out by a guest but was not currently occupied because the guest was at dinner with her grandma who had alzheimer's), and enters the room. he then picks up the television and starts to take it out of the room, but then hears people coming, drops the television, and runs away. carl is subsequently arrested and arraigned for burglary. assume that the crime of burglary requires that the following elements must be met: breaking and entering of a dwelling in the nighttime with an intent to commit a felon therein. additionally, assume that felony larceny applies if the value of the property exceeds $250.00. also assume that there are no cases that have interpreted the statute and no statutory definitions that apply.

Answer 1

Carl's Television Assume that there are no cases that have interpreted the statute and no statutory definitions that apply.We know 18 televisions sets contains 3 defective.

sets => 15 TV sets are ok.So the total number of possible ways for the hotel to buy = C = 43758

At least one of the defective sets, SO we need to find the probability for 1 defective sets, 2 defective sets and 3 defective sets.1. The number of ways the hotel purchases 8 of these televisions sets but have 1 defective one:P() = C * C =6435*3 = 19305

2. The number of ways the hotel purchases 8

of these televisions sets but have 2 defective

one:P(2) = C C = 5005*3= 15015

3. The number of ways the hotel purchases 8

of these televisions sets but have 3 defective

one:P(3) = C5 *=3003*1 = 3003

So the probability that the hotel receives at least

one of the defective sets =(P() + P(2) + P(3) ) /P= (19305 +15015 +3003 ) /43785*100% = 85.29%.

The number of ways the hotel can receive at

least one defective set in a purchase of 8 sets is

calculated using the combination.

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