Answer:
original number is 57
Step-by-step explanation:
I am not sure if there is a correct way to do this...but I am just guessing and checking to find the answer.
the possible 2 digit numbers that equal 12 are :
39,93,48,84,57,75,66
the number obtained by interchanging the digits exceeds the original number by 18....so the original number is 18 less then the new number.
the only two numbers whos difference is 18 is 57 and 75.....75 - 57 = 18
so the original number is 57.....and the new number obtained by interchanging the digits (75) exceeds the original number by 18...and 75 - 57 = 18.
Solution :
It is given that :
Casey boarded a Ferry wheel at position of 3 'o' clock.
The angular speed of the Ferry wheel = 5.6 radians per minute
The radius of the Ferry wheel = 50 feet
The height of the center wheel of the Ferry from the ground = 55 feet
Let the number of minutes be = t
a). The expression of the varying number of radians θ is given by :
After t minutes, θ = angle swept
θ = 5.6 t radians
b). Finding the height from the center of the wheel.
We know that : y = r sin θ
Given r = 50 feet
So, y = 50 sin (5.6 t) feet
Therefore, the height above the ground can be found by :
h = y + 55 (from ground)
h = 50 sin (5.6 t) + 55 feet
Answer:
<h2>x = 9, y = -72/5</h2>
Step-by-step explanation:
Given the 2 by 2 matrix ![A = \left[\begin{array}{-cc}x&5\\y&-8\\\end{array}\right]](https://tex.z-dn.net/?f=A%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7B-cc%7Dx%265%5C%5Cy%26-8%5C%5C%5Cend%7Barray%7D%5Cright%5D)
, we are to find the value of x and y for the expression A² = A to be true.
First we need to find A² by multiplying the same matrix together
![A^2 = \left[\begin{array}{-cc}x&5\\y&-8\\\end{array}\right] \left[\begin{array}{-cc}x&5\\y&-8\\\end{array}\right]\\\\ \ we \ normally \ multiply \ the \ rows \ of \ the \ first \ matrix \ with \ the \ column \ of \ the \ second \\\\A^2 = \left[\begin{array}{-cc}x^2+5y&5x-40\\xy-8y&5y+64\\\end{array}\right]\\\\Since \ A^2 = A,\ hence;\\\\\left[\begin{array}{-cc}x^2+5y&5x-40\\xy-8y&5y+64\\\end{array}\right] = \left[\begin{array}{-cc}x&5\\y&-8\\\end{array}\right]\\](https://tex.z-dn.net/?f=A%5E2%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7B-cc%7Dx%265%5C%5Cy%26-8%5C%5C%5Cend%7Barray%7D%5Cright%5D%20%5Cleft%5B%5Cbegin%7Barray%7D%7B-cc%7Dx%265%5C%5Cy%26-8%5C%5C%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5C%20%5C%20we%20%5C%20normally%20%5C%20multiply%20%5C%20the%20%5C%20rows%20%5C%20of%20%5C%20the%20%5C%20first%20%5C%20matrix%20%5C%20with%20%5C%20the%20%5C%20column%20%5C%20of%20%5C%20the%20%5C%20second%20%5C%5C%5C%5CA%5E2%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7B-cc%7Dx%5E2%2B5y%265x-40%5C%5Cxy-8y%265y%2B64%5C%5C%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5CSince%20%5C%20A%5E2%20%3D%20A%2C%5C%20hence%3B%5C%5C%5C%5C%5Cleft%5B%5Cbegin%7Barray%7D%7B-cc%7Dx%5E2%2B5y%265x-40%5C%5Cxy-8y%265y%2B64%5C%5C%5Cend%7Barray%7D%5Cright%5D%20%3D%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7B-cc%7Dx%265%5C%5Cy%26-8%5C%5C%5Cend%7Barray%7D%5Cright%5D%5C%5C)
Equating the first row and second column of both matrices together, we will have;
5x-40 = 5
add 40 to both sides of the equation
5x-40+40 = 5+40
5x = 45
x = 45/5
x = 9
Similarly, we will equate the second row and second column of both matrices to have;
5y+64 = -8
Subtract 64 from both sdies
5y+64-64 = -8-64
5y = -72
y = -72/5
<em>Hence the value of x is 9 and y is -72/5</em>
Answer:
It was answered correctly.
Step-by-step explanation:
Parenthesis means mutiplication so you can do iy rhat way or 4(c)^2=4×c^2.
Answer:
(B)
The elevation of the chameleon
Step-by-step explanation:
the fly is above the chameleon, so it's elevation should be represented by a positive number
