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Ratling [72]
1 year ago
13

HELP PLSS

Mathematics
1 answer:
atroni [7]1 year ago
8 0

The balloon reaches a height of 7 feet at 0.1 seconds and 2.13 seconds

<h3>How to determine the time the balloon is at the height?</h3>

The equation of the function is given as

h(t)= -16t^2 + 35t + 5

The above equation is a quadratic equation

When the balloon is at a height of 7 feet, we have

h(t) = 7

So, we have the following equations

h(t)= -16t^2 + 35t + 5

h(t) = 7

Next, we plot the equations on a graph (see attachment)

The equations intersect at

t = 0.059 and t = 2.129

Approximate

t = 0.1 and 2.13

Hence, the times are 0.1 seconds and 2.13 seconds

Read more about quadratic equation at

brainly.com/question/15709421

#SPJ1

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I NEED HELP PLZ ASAP , I AM SO STUCK ON THIS.
Bezzdna [24]

Function

d. 4f(t)

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5 0
2 years ago
Any help with this greatly appreciated.
Anestetic [448]

Put the equation in standard linear form.

x'(t) + \dfrac{x(t)}{t + 5} = 5e^{5t}

Find the integrating factor.

\mu = \exp\left(\displaystyle \int \frac{dt}{t+5}\right) = e^{\ln|t+5|} = t+5

Multiply both sides by \mu.

(t+5) x'(t) + x(t) = 5(t+5)e^{5t}

Now the left side the derivative of a product,

\bigg((t+5) x(t)\bigg)' = 5(t+5)e^{5t}

Integrate both sides.

(t+5) x(t) = \displaystyle 5 \int (t+5) e^{5t} \, dt

On the right side, integrate by parts.

(t+5) x(t) = \dfrac15 (5t+24) e^{5t} + C

Solve for x(t).

\boxed{x(t) = \dfrac{5t+24}{5t+25} e^{5t} + \dfrac C{t+5}}

3 0
2 years ago
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