In a triangle, the nomenclature is that a variable side a is opposite of the angle A. we can use the cosine law to determine the value of cosine A.
a2 = b2 + c2 -2bc cos a25 = 36 + 64 - 2*6*8 * cos acos a = 25/32
Answer:
C. x > -7 and x <= 3
Step-by-step explanation:
-3 < x + 4 <= 7
Subtract 4 from the three expressions.
-7 < x <= 3
-7 < x means x > -7.
Then you have x <= 3.
Answer: C. x > -7 and x <= 3
7x^2 - 16x - 8 = 0
using the quadratic formula x = [ -(-16)+/- sqrt((-16^2 - 4*7-8] / 2*7
= (16 +/1 sqrt 480) / 14
= 2.71, -0.42 to nearest hundredth
8c + 6j = 5p Subtract 6j from both sides
8c = 5p - 6j Divide both sides by 8
c = 
Answer:
x=20; vertical angles theorem
Step-by-step explanation:
hi! we can use the vertical angles theorem for this. vertical angles are congruent to each other, meaning they are the same amount of degrees. so, we can set 2x+10 and 50 equal to each other.
2x+10=50
2x=40
x=20
x=20 because of the vertical angles theorem.
