Question

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Answer 1

The value of x  in this triangle is $67.1^{o}$

The angle can be calculated as follows:

The first you should calculate the long of the side in front of the angle

as we know $c^{2}= a^{2}+ b ^{2}$

so  $a^{2}= c^{2}- b ^{2}$

     $a =\sqrt{ 72^{2}- 28 ^{2}}$ = 66.3

then we can calculate the angle of the triangle by calculate the sin of x

sin x = $\frac{66.3}{72}$

sin x = 0.92

x =$\sqrt{0.921}$ = $67.1^{o}$

hence, The value of x  in this triangle is $67.1^{o}$

Learn more on moles and molecules here : brainly.com/question/7537975

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