Ian's car can go 111 miles on 3 gallons of gas. During a drive last weekend he used 8 of gas. How far did Ian drive?
2 answers:
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First, you have to find out the values of the length and width.
Let l = length and w = width.
Set up your equation for area: l * w = 80
Set up your equation for perimeter: 2l + 2w = 36
We can use substitution for this problem, so find out the value of l or w. In this case, I will use the first equation to find out the value of l.
(Divide w on both sides) l = 80 / w
Since I know that l = 80 / w, I can substitute it into the second equation.
2l + 2w = 36, and l = 80 / w
= 2 (80/w) + 2w = 36
Simplify the equation.
= 160/w + 2w = 36
Get rid of the w in the denominator by multiplying the entire equation by w.
= ( 160/w + 2w = 36 ) * w
= 160 + = 36w
= 2 ( w - 8 ) ( w - 10 )
The solutions for width (w) is 8 or 10. Then, you can use both 8 and 10 as your length and width, either or is fine. Multiply by 4 for each of those values and you get 8 x 4 = 32 and 10 x 4 = 40. The new perimeter would be 2(32) + 2(40) =
a. 144 cm
Hope this helped you! Let me know if there are any confusions :)
Answer:
Explained below.
Step-by-step explanation:
The information provided is as follows:
(1)
A single mean test is to be performed in this case.
As the population standard deviation is not provided, a one-sample <em>t</em>-test will be used.
The correct option is b.
(2)
The null hypothesis is:
<em>H</em>₀: The average temperature in the population is 98.6°F, i.e. <em>μ </em>= 98.6°F.
The correct option is b.
(3)
The alternative hypothesis is:
<em>Hₐ</em>: The average temperature in the population is less than 98.6°F, i.e. <em>μ </em>< 98.6°F.
The correct option is c.
(4)
The standard deviation of the sample mean is as follows:
Thus, the value of SD is 0.3°F.
(5)
Compute the value of test statistic as follows:
Thus, the value of test statistic is -1.67.
(6)
The degrees of freedom of the test are:
df = n - 1
= 9 - 1
= 8
Thus, the degrees of freedom of the test is 8.