Given:
The two points are (-1,10) and (2,4).
To find:
The equation of line which passes though the given points.
Solution:
If a line passes through two points, then the equation of line is
![y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)](https://tex.z-dn.net/?f=y-y_1%3D%5Cdfrac%7By_2-y_1%7D%7Bx_2-x_1%7D%28x-x_1%29)
The line passes through (-1,10) and (2,4). So, the equation of line is
![y-10=\dfrac{4-10}{2-(-1)}(x-(-1))](https://tex.z-dn.net/?f=y-10%3D%5Cdfrac%7B4-10%7D%7B2-%28-1%29%7D%28x-%28-1%29%29)
![y-10=\dfrac{-6}{2+1}(x+1)](https://tex.z-dn.net/?f=y-10%3D%5Cdfrac%7B-6%7D%7B2%2B1%7D%28x%2B1%29)
![y-10=\dfrac{-6}{3}(x+1)](https://tex.z-dn.net/?f=y-10%3D%5Cdfrac%7B-6%7D%7B3%7D%28x%2B1%29)
![y-10=-2(x+1)](https://tex.z-dn.net/?f=y-10%3D-2%28x%2B1%29)
Using distributive property, we get
![y-10=-2x-2](https://tex.z-dn.net/?f=y-10%3D-2x-2)
Adding 10 both sides, we get
![y=-2x-2+10](https://tex.z-dn.net/?f=y%3D-2x-2%2B10)
![y=-2x+8](https://tex.z-dn.net/?f=y%3D-2x%2B8)
Therefore, the required equation of line is
.