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aivan3 [116]
1 year ago
8

Evaluate the expressions when x = 3; y = 4 & z = -2

Mathematics
1 answer:
WINSTONCH [101]1 year ago
7 0

Answer:

Sub in the numbers given to x, y, z and use calculator to solve

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Round 1.983 to the nearest hundredth
svet-max [94.6K]

Answer:

1.98

Step-by-step explanation:

Find the number in the hundredth place 8 and look one place to the right for the rounding digit 3. Round up if this number is greater than or equal to 5 and round down if it is less than 5.

4 0
3 years ago
Evaluate Dx / ^ 9-8x - x2^
Solnce55 [7]
It depends on what you mean by the delimiting carats "^"...

Since you use parentheses appropriately in the answer choices, I'm going to go out on a limb here and assume something like "^x^" stands for \sqrt x.

In that case, you want to find the antiderivative,

\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}

Complete the square in the denominator:

9-8x-x^2=25-(16+8x+x^2)=5^2-(x+4)^2

Now substitute x+4=5\sin y, so that \mathrm dx=5\cos y\,\mathrm dy. Then

\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}=\int\frac{5\cos y}{\sqrt{5^2-(5\sin y)^2}}\,\mathrm dy

which simplifies to

\displaystyle\int\frac{5\cos 
y}{5\sqrt{1-\sin^2y}}\,\mathrm dy=\int\frac{\cos y}{\sqrt{\cos^2y}}\,\mathrm dy

Now, recall that \sqrt{x^2}=|x|. But we want the substitution we made to be reversible, so that

x+4=5\sin y\iff y=\sin^{-1}\left(\dfrac{x+4}5\right)

which implies that -\dfrac\pi2\le y\le\dfrac\pi2. (This is the range of the inverse sine function.)

Under these conditions, we have \cos y\ge0, which lets us reduce \sqrt{\cos^2y}=|\cos y|=\cos y. Finally,

\displaystyle\int\frac{\cos y}{\cos y}\,\mathrm dy=\int\mathrm dy=y+C

and back-substituting to get this in terms of x yields

\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}=\sin^{-1}\left(\frac{x+4}5\right)+C
4 0
3 years ago
Simplify the expression to a polynomial in standard form.<br> (x-2)(x2 +7x +4)
goldenfox [79]

Answer:

Step-by-step explanation:

(x  - 2)(x² + 7x + 4) = x(x² + 7x + 4) - 2*(x² + 7x + 4)

                              = x*x² + x*7x + 4*x  - 2*x² -2* 7x -2* 4

                               = x³ + 7x² + 4x - 2x²  -14x -8

                                = x³ + <u>7x² - 2x²</u>    <u>+  4x - 14x</u> - 8

                                = x³ + 5x² - 10x - 8

5 0
2 years ago
ISTEP IS COMING UP AND IM NOT READY!!!
AlekseyPX

> and < with the lines under it mean that they can also be equal to the constant on the other side (greater/less than or equal to)

So x <= 3 can be anything less than 3 and 3.

*the = in this inequality is the equivalent of a line

Now vice versa.

x => 3 can be anything greater than 3 and 3.

Now for the dots.

The open dots in signs are (< and >).

Basically they start at that point they are on but don't include it.

So an open dot at 3 pointing to the left means that the value is greater than 3 but does not include 3.

The closed dots in signs are (<= and =>).

They start at the point and include it.

So a closed dot a 3 pointing to the left means that the value is greater than 3 and includes 3.

Arrows.

Arrows pointing to the left mean that the values are getting bigger.

Arrows pointing to the right mean that the values are getting smaller.

ie : An arrow pointing to the left with a starting point at 3 = 3 and anything bigger, such as 4.

ie : An arrow pointing to the right with a starting point at 3 = 3 and anything smaller, such as 2.

Solve for problems.

The main concept is isolate the variable.

This basically means make the variable be lonely ^^

Use +, -, *, and /

Ex : 6x + 2 > 3

First, we would subtract 2 from both sides.

6x > 1

Then, we would divide each side by 6, leaving the x alone.

x > 1/6

And voila! x is anything greater than 1/6 but it does not include 1/6.

Hope this helps! ^^

8 0
3 years ago
Read 2 more answers
You are choosing between two health clubs. Club A offers membership for a fee of $12 plus a monthly fee of $28. Club B offers me
EleoNora [17]

A has fixed one time fee of $12 and if you go to it say "m" months you pay $28 for each month, so your total cost at A is really 12 + 28m.

B has a fixed one time fee of $20 and if you go to it "m" months you pay $26 for each month, so you total cost at B is 20 + 26m.

how many months for the cost to be the same?

\stackrel{A}{12+28m}=\stackrel{B}{20+26m}\implies 12+2m=20\implies 2m=8\implies m=\cfrac{8}{2}\implies m=4

well, since the cost for both is the same, we can just get A's, knowing that B is the same

12+28(4)\implies 12+112\implies 124

5 0
2 years ago
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