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2 years ago

There are 3 arms for every 2 eyes. If there are 6 eyes, how many arms are there?

Mathematics

1 answer:

jeka942 years ago

7 0

Answer:

There are 9 arms.

Step-by-step explanation:

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Place value

s344n2d4d5 [400]

Expanded Notation:

A. 654.362 = (6x100) + (5x10) + (4x1) + (3x0.1) + (6x0.01) + (2x0.001)

B. 125.384 = (1x100) + (2x10) + (5x1) + (3x0.1) + (4x0.01) + (8x0.001)

8 0

2 years ago

Read 2 more answers

The manager of a bank recorded the amount of time each customer spent waiting in line during peak business hours one Monday. The

zavuch27 [327]

The standard deviation of the frequency distribution is 5.54

<h3>How to determine standard deviation?</h3>

The table of values is given as:

x f(x)

0-3 13

4-7 13

8-11 10

12-15 11

16-19 0

20-23 3

Rewrite the table by calculating the class midpoints:

x f(x)

1.5 13

5.5 13

9.5 10

13.5 11

17.5 0

21.5 3

Start by calculating the mean using:

$\bar x = \frac{\sum fx}{\sum f}$

This gives

$\bar x = \frac{1.5 * 13 + 5.5 * 13 + 9.5 * 10 + 13.5 * 11 + 17.5 * 0 + 21.5 * 3}{13 + 13 + 10 + 11 + 0 +3}$

Evaluate

$\bar x = 7.98$

The standard deviation is then calculated as:

$\sigma = \sqrt{\frac{\sum f(x - \bar x)^2}{\sum f }}$

So, we have:

$\sigma= \sqrt{\frac{13 * (1.5 - 7.98)^2 + 13 * (5.5 - 7.98)^2 + (9.5 - 7.98)^2 * 10 + (13.5 - 7.98)^2 * 11 + (17.5 - 7.98)^2 * 0 + (21.5 - 7.98)^2 * 3}{13 + 13 + 10 + 11 + 0 +3}}$

Evaluate

$\sigma= \sqrt{30.6496}$

Solve

$\sigma= 5.54$

Hence, the standard deviation is 5.54

Read more about standard deviation at:

brainly.com/question/15858152

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7 0

1 year ago

Let f(x) = ............

34kurt

Answer:

So first lets find g(-1)

so we plug in the answers:

-2 * -1 ^2 -4

-2*1-4 = -2-4 =

-6

Now lets solve for f(-2)

-2^2-3

4-3=1

-6+1 = 5

3*5 = 15

Im getting answer of 15 but it shows -15 or something, so I dont know if I got it wrong or if its like a dash then the answer.

3 0

2 years ago

What is the value of -3|15 - s| + 2s3 when's = -3

slamgirl [31]

6 0

3 years ago

If f(x) = 2x^2 - 5 and g(x) = 3x3, find (f-g)(x).

77julia77 [94]

$\text{Given that,}~ f(x) = 2x^2 -5 ~ \text{and}~ g(x) = 3x^3\\\\\text{Now,}\\\\ ~~(f-g)(x)\\\\=f(x) - g(x)\\\\=2x^2 -5 - 3x^3\\\\=-3x^3 +2x^2 -5$

4 0

1 year ago