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V125BC [204]
3 years ago
10

There are 3 arms for every 2 eyes. If there are 6 eyes, how many arms are there?

Mathematics
1 answer:
jeka943 years ago
7 0

Answer:

There are 9 arms.

Step-by-step explanation:

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10/3=?/9 and how do you get the answer
Anit [1.1K]
You get it by cross multiplication
10×9÷3=30 and if you want to check
30 over 9 =3.333
10 over 3 = 3.333
6 0
3 years ago
Read 2 more answers
Please help, thanks. I don't understand how to do this.​
konstantin123 [22]

Answer:

3m(a-2b)+(a-2b)^2

= 3m(a-2b)+(a-2b)(a-2b)

= (a-2b)(3m+a-2b)

6 0
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Find the angle the line 3y =2x + 6 makes with the x axis​
Artemon [7]
Find the angle between lines; 0.5880 rad, 33.7°
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6 0
2 years ago
PLEASE HELP ME PLZ PLZ PLZ
Oksana_A [137]

Answer:

4

Step-by-step explanation:

pythagoras theorem = a* + b* = c* ( by '*' i mean squared)

2* + b* = square root twenty

4 + b* = 20

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4 0
3 years ago
Is anyone wanna help me?
PtichkaEL [24]

Answer:

See the answers bellow

Step-by-step explanation:

For 51:

Using the definition of funcion, given f(x) we know that different x MUST give us different images. If we have two different values of x that arrive to the same f(x) this is not a function. So, the pair (-4, 1) will lead to something that is not a funcion as this would imply that the image of -4 is 1, it is, f(-4)=1 but as we see in the table f(-4)=2. So, as the same x, -4, gives us tw different images, this is not a function.

For 52:

Here we select the three equations that include a y value that are 1, 3 and 4. The other values do not have a y value, so if we operate we will have the value of x equal to a number but not in relation to y.

For 53:

As he will spend $10 dollars on shipping, so he has $110 for buying bulbs. As every bulb costs $20 and he cannot buy parts of a bulb (this is saying you that the domain is in integers) he will, at maximum, buy 5 bulbs at a cost of $100, with $10 resting. He can not buy 6 bulbs and with this $10 is impossible to buy 0.5 bulbs. So, the domain is in integers from 1 <= n <= 5. Option 4.

For 54:

As the u values are integers from 8 to 12, having only 5 possible values, the domain of the function will also have only five integers values, With this we can eliminate options 1 and 2 as they are in real numbers. Option C is the set of values for u but not the domain of c(u). Finally, we have that 4 is correct, those are the values you have if you replace the integer values from 8 to 12 in c(u). Option 4.

6 0
3 years ago
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