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Dovator [93]
1 year ago
8

Which of the following could be the rectangle's length and width?

Mathematics
1 answer:
Tpy6a [65]1 year ago
6 0

The possible rectangle's length and width are A) 1 cm and 15 cm and C) 3 cm and 5 cm

<h3>How to determine the possible rectangle's length and width?</h3>

The given parameters are

Area = 15 square cm

The area is given as

Area = 15 square cm

The formula of area is

Area = Length x Width

Using the above formula, we have:

A) 1 cm and 15 cm ⇒ 15 square cm

B) 2 cm and 7 cm ⇒ 14 square cm

C) 3 cm and 5 cm ⇒ 15 square cm

D) 4 cm and 4 cm ⇒ 16 square cm

Hence, the possible rectangle's length and width are A) 1 cm and 15 cm and C) 3 cm and 5 cm

Read more about area at:

brainly.com/question/17335144

#SPJ1

<u>Possible question</u>

The area of a rectangle is 15 square cm

Which of the following could be the rectangle's length and width?

(Area = length x width)

Choose all answers that apply:

A) 1 cm and 15 cm

B) 2 cm and 7 cm

C) 3 cm and 5 cm

D) 4 cm and 4 cm

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Select all that apply please
Digiron [165]

Answer:

i think it's x=0 and 0=1

6 0
3 years ago
Read 2 more answers
What number replaces the Δ?
OleMash [197]
1 + 3 = Δ + 3

By comparing

Δ = 1.

Option A.


3 0
3 years ago
5/4 to 3/8 as a percent change
Digiron [165]
Well, what's the diffrence from 5/4 to 3/8?

\bf \cfrac{5}{4}-\cfrac{3}{8}\qquad \stackrel{\textit{LCD is 8 clearly}}{\implies }\qquad \cfrac{10-3}{8}\implies \cfrac{7}{8}

so, if we take 5/4 to be the 100%, what is 7/8 off of it in percentage anyway?

\bf \begin{array}{ccll}&#10;amount&\%\\&#10;\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\&#10;\frac{5}{4}&100\\\\&#10;\frac{7}{8}&x&#10;\end{array}\implies \cfrac{\quad \frac{5}{4}\quad }{\frac{7}{8}}=\cfrac{100}{x}\implies \cfrac{5}{4}\cdot \cfrac{8}{7}=\cfrac{100}{x}&#10;\\\\\\&#10;\cfrac{40}{28}=\cfrac{100}{x}\implies x=\cfrac{28\cdot 100}{40}
5 0
3 years ago
A baseball player hit 6060 home runs in a season. Of the 6060 home​ runs, 1919 went to right​ field, 2020 went to right center​
m_a_m_a [10]

Answer: (a) 0.317

               (b) 0.167

                (c) Not unusual

Step-by-step explanation:

Probability is defined as the chance of an event occurring.

Let S be a sample space and A be an event in the sample space, the probability of event A occurring can be found using the following:

P(A) = n(A) divided by n(S) where n(A) = number of elements in event A and n(S) = number of elements in the sample space.

(a) P(Right field) = Number of hits to the right field divided by total number of hits

                          = 1919/6060

                          =  19/60  which is approximately equal to 0.317

(b) P(Left field) = 1010/6060

                         = 1/6 which is approximately equal to 0.167

(c)  The probability that the home run was hit to the left field is 0.167.

    The probability of an unusual event is 0, therefore, it is possibly for the

    player to hit a home run to the left.        

8 0
3 years ago
Find the volume of the figures.A. 907.5 cmB. 126ncmC. 605 cmD. 55 cm
-BARSIC- [3]

We have the next formula to calculate the volume

V=\frac{1}{3}\cdot a^2\cdot h

where a is the length of the side in the base and h is the height

a=11cm

h=15cm

we substitue the values in the formula

V=\frac{1}{3}\cdot11^2\cdot15=605\operatorname{cm}^3

8 0
1 year ago
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