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3 years ago

Answer this and add work, show all work for math. :P

Mathematics

2 answers:

Andreyy893 years ago

8 0

Lines are in the form y=mx+b, where m is the slope and b is the y-intercept. This line is thus y=9/4x-14, so C is correct. Multiplying by four, we get 4y=9x-56. Adding 56 and subtracting 4y, we see that 9x-4y=56, and multiplying by -1, we get 4y-9x=-56, so A is also correct. At this point, it is clear that B and D are incorrect, so A and C only are correct.

balandron [24]3 years ago

4 0

You know that you can spot the slope and intercept right away
IF you 'solve' the equation for 'y'. Then you'll have

y = (slope) x + (intercept) .

So for choices 'A' and 'B', you have to massage the equation
into the standard form, and then just look at it and see whether
the slope is 9/4 and the intercept is -14.

A).         -9x + 4y =   -56

Add 9x to each side:    4y = 9x - 56

Divide each side by 4 :   y = 9/4 x - 14    <== Yes ! Good one.

B). 9x + 4y = 56

Subtract 9x from each side:   4y = -9x   + 56

Divide each side by 4 :       y = -9/4 + 14 <= no, signs are wrong

C). Yes. Slope is 9/4 and intercept is -14 .

D). No. Slope is 9/4 alright, but intercept is +14, not -14 .

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4 years ago

A random sample of 49 measurements from one population had a sample mean of 15, with sample standard deviation 5. An independent

kotykmax [81]

Answer:

Comparing the p value with the significance level $\alpha=0.01$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and the difference between the two groups is significantly different.

Step-by-step explanation:

$\bar X_{1}=15$ represent the mean for sample 1

$\bar X_{2}=18$ represent the mean for sample 2

$s_{1}=5$ represent the sample standard deviation for 1

$s_{f}=6$ represent the sample standard deviation for 2

$n_{1}=49$ sample size for the group 2

$n_{2}=64$ sample size for the group 2

$\alpha=0.01$ Significance level provided

t would represent the statistic (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to check if the difference in the population means, the system of hypothesis would be:

Null hypothesis: $\mu_{1}-\mu_{2}=0$

Alternative hypothesis: $\mu_{1} - \mu_{2}\neq 0$

We don't have the population standard deviation's, so for this case is better apply a t test to compare means, and the statistic is given by:

$t=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}}$ (1)

And the degrees of freedom are given by $df=n_1 +n_2 -2=49+64-2=111$

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

With the info given we can replace in formula (1) like this:

$t=\frac{(15-18)-0}{\sqrt{\frac{5^2}{49}+\frac{6^2}{64}}}}=-2.897$

P value

Since is a bilateral test the p value would be:

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3 years ago

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The only way for YOU to answer this question is to solve the equations first.

And if you want someone ELSE to tell the math concepts and principles that
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4 years ago

Last month a cafe had 3200 customers 600 of them ordered gluten-free meals

algol [13]

Answer: 18.75%

Step-by-step explanation:

Here is the complete question:

Last month, a cafe had 3200 customers. 600 of them ordered gluten-free meals. What percentage of the customers ordered gluten-free meals?

To find the percentage of the customers who ordered gluten-free meals, we will divide the number of people who ordered glutton free meal by the total number of customers and then multiply by 100. This will be:

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3 years ago