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3 years ago

First convert these fractions to twelfths then order them.Write your

Mathematics

1 answer:

sergiy2304 [10]3 years ago

8 0

Here’s the link to the answer

Curlylips444.com

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What is the domain of the function f(x) = 2x + 5?

alukav5142 [94]

There is no value that x cannot be for linear equations.

Thus, the domain is ALL REAL NUMBERS.

CHOICE B.

8 0

3 years ago

If the distance covered by an object in time t is given by s(t)=t^2+5t , where s(t) is in meters and t is in seconds, what is th

alisha [4.7K]

Answer:

E. 44 meters

Step-by-step explanation:

The function that models the distance covered by the object is

$s(t)=t^2+5t$

where s(t) is in meters and t is in seconds.

The distance covered by the object after 1 second is

$s(1)=1^2+5(1)=6m$

The distance covered by the object after 1 second is

$s(1)=5^2+5(5)=50m$

The distance covered between 1 second and 5 seconds is

50-6=44m

6 0

3 years ago

Identify the surface with the given vector equation. r(s, t) = s sin 4t, s2, s cos 4t

k0ka [10]

Answer:

Circular paraboloid

Step-by-step explanation:

Given ,

$r(s,t)=ssin4t,s^2,scos4t$

Here, these are the respective $x,y,z$ axes components.

Component along x axis $r_i : ssin4t$

Component along y axis $r_j : s^2$

Component along z axis $r_k : scos4t$

We see that , from the parameterised equation , $r_i^2+r_k^2=s^2sin^24t+s^2cos^24t\\r_i^2+r_k^2=s^2\\r_i^2+r_k^2=r_j$

This can also be written as :

$x^2+z^2=y$

This is similar to an equation of a parabola in 1 Dimension.

By fixing the value of z=0,

We get $y=x^2$ which is equation of a parabola curving towards the positive infinity of y-axis and in the x-y plane.

By fixing the value of x=0,

We get $y=z^2$ which is equation of a parabola curving towards positive infinity of y-axis and in the y-z plane.

Thus by fixing the values of x and z alternatively , we get a CIRCULAR PARABOLOID.

4 0

3 years ago

Ms. Mincey wants to spend less than $80 on presents for her 2 brothers. What is the most amount of money she can spend on each o

TiliK225 [7]

Answer:

49 each!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

4 0

3 years ago

Read 2 more answers

Actual lengths of pregnancy terms for a particular species of mammal are nearly normally distributed about a mean pregnancy leng

HACTEHA [7]

Solution :

The data is normally distributed.

The standard deviation is 18 days

Here the data is normally distributed and 54 days is 3 days of standard deviation.

Therefore, the percentage of the births that would be $\text{expected to occur}$ within the 54 days of the mean $\text{pregnancy}$ length is given by :

= P( -3 < Z < 3)

= 0.9544

= 95 %

Therefore, about 95% of the births would be $\text{expected to occur}$ within 54 days of the men $\text{pregnancy}$ length.

8 0

2 years ago