First convert these fractions to twelfths then order them.Write your

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jek_recluse [69]

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Nutka1998 [239]

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Shtirlitz [24]

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quester [9]

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zloy xaker [14]

$\bf \cfrac{p+2}{p+7}=\cfrac{3}{6}\implies \cfrac{p+2}{p+7}=\cfrac{1}{2}\implies 2(p+2)=1(p+7)\implies 2p+4=p+7 \\\\\\ p+4=7\implies p=3$

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