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Fofino [41]
1 year ago
8

In the blosum-62 substitution matrix, a large ________________ score corresponds to substitution that occurs frequently.

Chemistry
1 answer:
Svetllana [295]1 year ago
3 0

In the blosum-62 substitution matrix, a large positive score corresponds to substitution that occurs frequently.

BLOSUM-62 is used to account for the type of substitution when comparing sequences. To identify the problem the first approach is examining the substitutions that have actually taken place in evolutionary related proteins.

From an examination of appropriately aligned sequences, substitution matrices have been deduced. A substitution matrix describes a scoring system for the replacement of any amino acid with each of the other 19 amino acids.

In these matrices, a large positive score corresponds to a substitution that only occurs relatively frequently, whereas a large negative score corresponds to a substitution that only occurs rarely. A commonly used matrix, the BLOSUM-62 stands for Blocks of amino acid substitution matrix.

Each column in the matrix represents one of the 20 amino acids, whereas the position of the single letter codes within each column specify the score for the corresponding substitution.

To learn more about BLOSUM-62 here

brainly.com/question/15149277

#SPJ4

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Find the initial temperature of 45.0g of water if its final Temperature after submerging a metal with the mass of 8.5g is 22.0°C
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The initial temperature of the water that resulted in the final temperature of the water-metal mixture is 20.7 ⁰C.

<em>"Your question is not complete, it seems to be missing the following information;"</em>

the specific heat capacity of the metal is 0.45 J/g⁰C.

The given parameters;

  • <em>mass of water, </em>m_w<em> = 45 g</em>
  • <em>final temperature of the water, </em>t_w<em> = 22 ⁰C</em>
  • <em>mass of the metal, m = 8.5 g</em>
  • <em>initial temperature of the metal, t = 82 ⁰C.</em>
  • <em>specific heat capacity of the metal, c = 0.45 J/g⁰C.</em>

The initial temperature of the water will be calculated by applying the principle of conservation of energy;

<em>heat gained by water = heat lost by metal</em>

Q_{water} = Q_{metal}

m_wc_w \Delta t_w = mc\Delta t

where;

c_w <em>is the specific heat capacity of the water = 4.184 J/g⁰C.</em>

<em />

<em>Substitute the given values;</em>

45 x 4.184 x (22 - t) = 8.5 x 0.45 x (85 - 22)

4142.16  - 188.28t = 240.98

188.28t  = 4142.16  - 240.98

188.28t  = 3901.18

t = \frac{3901.18}{188.28} \\\\t = 20.7 \ ^0 C

Thus, the initial temperature of the water that resulted in the final temperature of the water-metal mixture is 20.7 ⁰C.

Learn more here:brainly.com/question/15345295

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