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Alchen [17]
3 years ago
5

When cool, dense air from over the water flows inland, it's called a ____. a. land breeze c. jet stream b. polar easterly d. sea

breeze
Chemistry
2 answers:
AlekseyPX3 years ago
8 0
When cool, dense air from over the water flows inland, it's called a sea breeze.

God bless!
salantis [7]3 years ago
4 0

Answer: Option (d) is the correct answer.

Explanation:

When cool, dense air from over the water flows inland, it's called a sea breeze.

Any wind that travels from large body of water towards the inland is known as sea breeze. Land absorbs heat from the sun more readily as compared to water in the sea.

Therefore, the wind above the land is warm whereas the wind above the sea is cooler and dense.

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Na2CO3 + 2HCl ---------> 2NaCl + CO2 + H2O How many moles of NaCl are produced from the reaction of 1.67 x 1022 molecules of
dexar [7]

Answer:

0.0554 moles of NaCl are produced from the reaction of 1.67*10²² molecules of Na₂CO₃ with excess HCl.

Explanation:

The balanced reaction is:

Na₂CO₃ + 2 HCl → 2 NaCl + CO₂ + H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of each compound participate in the reaction:

  • Na₂CO₃: 1 mole
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On the other hand, Avogadro's Number is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023*10²³ particles per mole. Avogadro's number applies to any substance.

In this case, you can apply the following rule of three: if 6.023*10²³ molecules of Na₂CO₃ are contained in 1 mole, 1.67*10²² molecules will be contained in how many moles?

amount of moles=\frac{1.67*10^{22}molecules*1mole }{6.023*10^{23}molecules}

amount of moles= 0.0277 moles

In this case, you can apply the following rule of three: if by stoichiometry 1 mole of Na₂CO₃ produces 2 moles of NaCl, 0.0277 moles of Na₂CO₃ will produce how many moles of NaCl?

amount of moles of NaCl=\frac{0.0277 moles of Na_{2} CO_{3}*2 moles of NaCl }{1 mole of Na_{2} CO_{3}}

amount of moles of NaCl= 0.0554 moles

<u><em>0.0554 moles of NaCl are produced from the reaction of 1.67*10²² molecules of Na₂CO₃ with excess HCl.</em></u>

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