The number of real zeros of the function f(x) = x3 + 4x2 + x − 6 is 3
<h3>How to determine the number of real zeros?</h3>The equation of the function is given as:
Expand the function
Reorder the terms
Factor the expression
Factor out x -1
Expand
Factorize
Factor out x + 2
The function has been completely factored and it has 3 linear factors
Hence, the number of real zeros of the function f(x) = x3 + 4x2 + x − 6 is 3
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The interval of the provided inequality expression is -5/9 to the infinity [(-5/9),∞) using the table of signs to solve the inequality.
<h3>What is the inequality equation?</h3>Inequality equation is the equation in which the two expressions are compared with greater than, less than or other inequality signs.
The inequality given in the problem is,
Simplify the equation first by adding the same terms,
Now in this case, if the value x is ranges from -5/9 to infinity.
Thus, the interval of the provided inequality expression is -5/9 to the infinity [(-5/9),∞) using the table of signs to solve the inequality.
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