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r-ruslan [8.4K]
10 months ago
9

What are examples of scanning devices?

Computers and Technology
1 answer:
eimsori [14]10 months ago
4 0

Here the examples of scanning devices :

  • Drum Scanner.
  • Handheld Scanner.
  • Flatbed Scanner.
  • Optical Character Recognition.
  • Magnetic Ink Character Recognition.
  • Image Scanner.

<h3>What is meant by scanning ?</h3>
  • A text is scanned quickly in order to find a specific piece of information. In daily life, scanning is regularly used for tasks like looking up a word in a dictionary or finding a friend's name in your phone's contacts list.
  • Scanners may basically be divided into three categories. These consist of network scanning, port scanning, and vulnerability scanning.
  • There are three different types of scanners: portable scanners, flatbed scanners, and drum scanners. While flatbed scanners are commonly used in offices and classrooms, drum scanners are mainly used in the publishing industry to print high-quality pictures.
  • Three processes make up the basic scanning process: scan, register, and detail.

Learn more about scanning refer to :

brainly.com/question/25106178

#SPJ4

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Answer:

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if "mold" in word:

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else:

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Explanation:

7 0
3 years ago
NEED HELP
valentina_108 [34]
It’s string. you can make the string bounce and make a sound.
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Write a program that lets the user enter the total rainfall for each of 12 months into a vector of doubles. The program will als
madam [21]

Answer:

Explanation:

#include<iostream>

#include<iomanip>

#include<vector>

using namespace std;

double getAverage(const vector<double> amounts)

{

   double sum = 0.0;

   for (int i = 0; i < amounts.size(); i++)

       sum += amounts[i];

   return(sum / (double)amounts.size());

}

int getMinimum(const vector<double> amounts)

{

   double min = amounts[0];

   int minIndex = 0;

   for (int i = 0; i < amounts.size(); i++)

   {

       if (amounts[i] < min)

       {

           min = amounts[i];

           minIndex = i;

       }

   }

   return minIndex;

}

int getMaximum(const vector<double> amounts)

{

   double max = amounts[0];

   int maxIndex = 0;

   for (int i = 0; i < amounts.size(); i++)

   {

       if (amounts[i] > max)

       {

           max = amounts[i];

           maxIndex = i;

       }

   }

   return maxIndex;

}

int main()

{

   vector<string> months;

   vector<double> rainfalls;

   months.push_back("January");

   months.push_back("February");

   months.push_back("March");

   months.push_back("April");

   months.push_back("May");

   months.push_back("June");

   months.push_back("July");

   months.push_back("August");

   months.push_back("September");

   months.push_back("October");

   months.push_back("November");

   months.push_back("December");

   cout << "Input 12 rainfall amounts for each month:\n";

   for (int i = 0; i < 12; i++)

   {

       double amt;

       cin >> amt;

       rainfalls.push_back(amt);

   }

   cout << "\nMONTHLY RAINFALL AMOUNTS\n";

   cout << setprecision(2) << fixed << showpoint;

   for (int i = 0; i < 12; i++)

       cout << left << setw(11) << months[i] << right << setw(5) << rainfalls[i] << endl;

   cout << "\nAVERAGE RAINFALL FOR THE YEAR\n" << "Average: " << getAverage(rainfalls) << endl;

   int minIndex = getMinimum(rainfalls);

   int maxIndex = getMaximum(rainfalls);

   cout << "\nMONTH AND AMOUNT FOR MINIMUM RAINFALL FOR THE YEAR\n";

   cout << months[minIndex] << " " << rainfalls[minIndex] << endl;

   cout << "\nMONTH AND AMOUNT FOR MAXIMUM RAINFALL FOR THE YEAR\n";

   cout << months[maxIndex] << " " << rainfalls[maxIndex] << endl;

   return 0;

}

3 0
2 years ago
What is the output of the following code fragment? int i = 1; int sum = 0; while (i &lt;= 11) { sum = sum + i; i++; } System.out
valentina_108 [34]

Answer:

The value of sum is 66

Explanation:

i = 1

sum = 0

while (i <= 11) {  

sum = sum + i;

i++;  

}

i = 1

  • sum = sum + i
  • sum = 0 + 1
  • sum = 1

i = 2

  • sum = sum + i
  • sum = 1 + 2
  • sum = 3

i = 3

  • sum = sum + i
  • sum = 3 + 3
  • sum = 6

i = 4

  • sum = sum + i
  • sum = 6 + 4
  • sum = 10

i = 5

  • sum = sum + i
  • sum = 10 + 5
  • sum = 15

i = 6

  • sum = sum + i
  • sum = 15 + 6
  • sum = 21

i = 7

  • sum = sum + i
  • sum = 21 + 7
  • sum = 28

i = 8

  • sum = sum + i
  • sum = 28 + 8
  • sum = 36

i = 9

  • sum = sum + i
  • sum = 36 + 9
  • sum = 45

i = 10

  • sum = sum + i
  • sum = 45 + 10
  • sum = 55

i = 11

  • sum = sum + i
  • sum = 55 + 11
  • sum = 66

i = 12 --> does not comply with the condition "i < = 11", the while loop is over

7 0
3 years ago
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